4t=r
a=pir^2
sub 4t for r
a=pi(4t)^2
a=pi16t^2
a(t)=16pi(t^2)
A. a(t)=16pi(t^2)
B. sub 4 for t
a(4)=16pi4^2
a(4)=16pi16
a(4)=16*16*3.14
a(4)=803.84 square units
A. a(t)=16pi(t^2)
B. 803.84 square units
The correct answer is <span>C:Greater hours worked, fewer hours spent talking on the phone.
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Answer:
Part 1) 
Part 2) 
Step-by-step explanation:
The picture of the question in the attached figure
Part 1
Find the length side AB
we know that
----> by SOH (opposite side divided by the hypotenuse)
substitute the given values

solve for AB

Part 2
Find the length side AC
we know that
----> by TOA (opposite side divided by the adjacent side)
substitute the given values

solve for AC

Answer:
1269 square meters
Step-by-step explanation:
The path and the plot of land form two concentric circles (they have the same center). The radius of the plot of land is 100m (half of the diameter) and the radius of the larger circle, formed by putting a 2m wide path around the plot of land, is 102m. Thus, the area of the path is
minus
which will be
which is
. Estimate
to 3.141 and calculate, getting 1268.964... which is 1269, rounded to the nearest square meter.
Hope this helps :)