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4 years ago

Good Morning! I have a question-

2 answers:

8 0

You can use the equivalent formula d = rt which means distance equals rate times time. To solve for speed or rate use the formula for speed, s = d/t which means speed equals distance divided by time. To solve for time use the formula for time, t = d/s which means time equals distance divided by speed.

yaroslaw [1]4 years ago

5 0

Time divided by distance = speed

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580 nm light shines on a double slit with d=0.000125 m. What is the angle of the third dark interference minimum (m=3)?

Dmitry_Shevchenko [17]

Answer:

0.66 degrees

Explanation:

The computation of the angle of the third dark interference is shown below:

The condition of the minima is

Path difference = (2n +1) × $\lambda$ ÷ 2

For third minima, n = 2

Now

xd ÷ D = (2 × 2 + 1) × $\lambda$ ÷ 2

d tan Q_3 = 5 $\lambda$ ÷ 2

tan Q_3 = 5 $\lambda$ ÷ 2d

Q_3 = tan^-1 × (5 $\lambda$ ÷2d)

= tan^-1 × (5 × 580 × 10^-9) ÷ (2 × 0.000125)

= 0.66 degrees

5 0

3 years ago

Calculate the ratio of the drag force on a passenger jet flying with a speed of 1200 km/h at an altitude of 10 km to the drag fo

Sonbull [250]

Answer:

$2.267$

Explanation:

Drag force is given by

$F=\dfrac{1}{2}\rho Av^2C$

C = Drag coefficient is constant

A = Area is constant

$v_1$ = Velocity of the passenger jet = 1200 km/h = $\dfrac{1200}{3.6}\ \text{m/s}$

$v_2$ = Velocity of the prop plane = $\dfrac{1}{4}v_1$

$\rho_1$ = Density of the air where the jet was flying = $0.38\ \text{kg/m}^3$

$\rho_2$ = Density of the air where the prop plane was flying = $0.67\ \text{kg/m}^3$

$F\propto \rho v^2$

$\dfrac{F_1}{F_2}=\dfrac{\rho_1 v_1^2}{\rho_2 v_2^2}\\\Rightarrow \dfrac{F_1}{F_2}=\dfrac{0.38 v_1^2}{0.67 (\dfrac{1}{4}v_1^2)}\\\Rightarrow \dfrac{F_1}{F_2}=2.267$

The ratio of the drag forces is $2.267$ .

5 0

3 years ago

Answer ASAP and only if you know its correct <br> this is science btw

kvv77 [185]

Answer:

jupiter

Explanation:

from the list, Jupiter is closest to the sun.

4 0

3 years ago

A proton orbits a long charged wire, making 1.80 ×106 revolutions per second. The radius of the orbit is 1.20 cm What is the wir

Fantom [35]

Answer:

linear charge density = -9.495 × $10^{-34}$ C/m

Explanation:

given data

revolutions per second = 1.80 × $10^{6}$

radius = 1.20 cm

solution

we know that when proton to revolve around charge wire then centripetal force is require to be in orbit of radius around provide by electric force

- q × E = m × w² × r ..................1

- 9 × $10^{9}$ × $\frac{2*linear\ charge\ density}r}$ q = m × w² × r ............2

and w = $\frac{2*\pi}{T}$

w = $\frac{d\theta }{dt}$

w = 1.80 × $10^{6}$ × $\frac{2*\pi}{1}$

w = 11304000 rad/s

so here from equation 2

- 9 × $10^{9}$ × $\frac{2*linear\ charge\ density}{0.012}$ 1.80 × $10^{6}$ = 1.672 × $10^{-27}$ × 11304000² × 0.0120

linear charge density = -9.495 × $10^{-34}$ C/m

8 0

3 years ago

uranus is much smaller and less massive than jupiter. uranus rotates on its side, giving it extreme seasons. this may have been

Tresset [83]

The correct statements from the following list about how Uranus is different from Jupiter, and how its rings and moons formed and evolved includes the following:

Uranus is much smaller and less massive than Jupiter.
Uranus's appearance is nearly featureless; very bland.
Uranus has some large moons and rings.
Uranus rotates on its side, giving it extreme seasons. This may have been caused by an impact.

Describe Uranus?

Uranus is described as the seventh planet from the Sun. The name Uranus is a reference to the Greek god of the sky, Uranus, who, according to Greek mythology, was the great-grandfather of Ares, grandfather of Zeus and father of Cronus.

Some known facts about Uranus includes the following:

Uranus is the coldest planet in the Solar System
Uranus orbits the Sun on its side
A Season on Uranus lasts one long day which is equal to 42 years
Uranus is the second-least dense planet.

Learn more about Uranus at: brainly.com/question/13770002

#SPJ4

7 0

1 year ago