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const2013 [10]
3 years ago
14

2.1kilograms into grams (1000g=1kg)

Physics
1 answer:
Feliz [49]3 years ago
4 0

Answer:

2100 grams

Explanation:

You multiply 2.1 kg by 1000

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The pressure of the earth's atmosphere at sea level is 14.7 lb/in2. What is the pressure when expressed in g/m2? (2.54 cm = 1 in
miss Akunina [59]
<h2>Answer:</h2>

14.7 lb / in² = 10333018.166 g / m²

<h2>Explanation:</h2>

Given from the question;

pressure = 14.7lb/in²

<u>To convert from lb / in² to g / m²</u>

Note;

2.54 cm = 1 in       ------------(i)

But;

100 cm = 1m

=> 2.54cm = 2.54 cm x 1 m / 100 cm = 0.0254m

=>2.54cm = 0.0254m

Substitute 2.54cm = 0.0254m into equation(i)

=> 0.0254m = 1 in

<em>Note also;</em>

2.205 lb = 1 kg            ------------------(ii)

But;

1kg = 1000g

Substitute 1kg = 1000g into equation (ii)

=> 2.205 lb = 1000g   ---------------------(iii)

<em>From equation(iii);</em>

if, 2.205 lb = 1000g

then, 1 lb = 1 lb x 1000 g / 2.205 lb = 453.5g

=> 1 lb = 453.5 g

<em>Now let's convert 14.7 lb/in² to g / m²;</em>

=> 14.7 lb / in² could be written as 14.7 x 1 lb / (1 in x 1 in)

i.e

=> 14.7 lb / in² = 14.7 x 1 lb / (1 in x 1 in)     ------------------(iv)

<em>Substitute the values of 1 lb = 453.5g and 1 in = 0.0254m into equation(iv)</em>

=> 14.7 lb / in² = 14.7 x 453.5g / (0.0254m x 0.0254m)

=> 14.7 lb / in² = 6666.45 g / (0.00064516m²)

=> 14.7 lb / in² = 10333018.166 g / m²

<em>Therefore, 14.7 lb / in² = 10333018.166 g / m²</em>

5 0
3 years ago
When a net force of 17.0 newtons is applied to a dictionary placed on a frictionless table, it accelerates by 3.75 meters/second
4vir4ik [10]
Force = (mass) x (acceleration)    (Newton's second law of motion)

Divide both sides of the equation by 'acceleration', and you have

Mass = (force) / (acceleration)

Mass = 17 newtons / 3.75 meters per second-sqrd = 4.533 kilograms (rounded)
8 0
3 years ago
A window has a glass surface of 2907 cm2 and a thickness of 5.6 mm. Find the rate of energy transfer by conduction through this
butalik [34]

Answer:

2.30714 W

-16.38071 W

Explanation:

k = Heat conduction coefficient = 0.8 W/(m·°C)

A = Area = 2907 cm²

l = Thickness = 5.6 mm

T_2 = Outside temperature

T_1 = Inside temperature

Rate of heat transfer is given by

Q=\frac{kA(T_2-T_1)}{l}\\\Rightarrow Q=\frac{0.8\times 2907\times 10^{-6}\times (81-71)\times \frac{5}{9}}{5.6\times 10^{-3}}\\\Rightarrow Q=2.30714\ W

The rate of energy transfer is 2.30714 W

Q=\frac{kA(T_2-T_1)}{l}\\\Rightarrow Q=\frac{0.8\times 2907\times 10^{-6}\times (0-71)\times \frac{5}{9}}{5.6\times 10^{-3}}\\\Rightarrow Q=-16.38071\ W

The rate of energy transfer is -16.38071 W

7 0
3 years ago
If the outside air temperature increases during a flight at constant power and at a constant indicated altitude, the true airspe
Readme [11.4K]

The true airspeed will increase and true altitude will increase.

<h3>What is true air speed?</h3>

True airspeed is the airspeed of an aircraft relative to undisturbed air.

It's the aircraft speed relative to the airmass in which it's flying.

<h3>How does outside air temperature affect air speed?</h3>

If the outside air temperature increases during a flight at constant power and at a constant indicated altitude, the true airspeed will increase and true altitude will increase.

Thus, the true airspeed will increase and true altitude will increase.

Learn more about true airspeed here: brainly.com/question/13257916

#SPJ1

6 0
2 years ago
The major problem with hydrogen as an alternative source of energy is that none exists on the surface of the earth. True or fals
Brut [27]
That statement is as false as false can be.

Roughly 78% of the Earth's surface is covered by water,
and Hydrogen is a major component of water. 

On the surface of the Earth, you really have to try hard
to be far away from a cheap source of Hydrogen.


8 0
3 years ago
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