2.1kilograms into grams (1000g=1kg)

A wave pulse travels along a stretched string at a speed of 100 cm/s. What will be the speed in cm/s if the string's tension is

makvit [3.9K]

Answer:

The new velocity of the string is 100 centimeters per second (1 meter per second).

Explanation:

The speed of a wave through a string ( $v$ ), in meters per second, is defined by the following formula:

$v = \sqrt{\frac{T\cdot L}{m} }$ (1)

Where:

$T$ - Tension, in newtons.

$L$ - Length of the string, in meters.

$m$ - Mass of the string, in kilograms.

The expression for initial and final speeds of the wave are:

Initial speed

$v_{o} = \sqrt{\frac{T_{o}\cdot L_{o}}{m_{o}} }$ (2)

Final speed

$v = \sqrt{\frac{(4\cdot T_{o})\cdot (0.5\cdot L_{o})}{2\cdot m_{o}} }$

$v = \sqrt{\frac{T_{o}\cdot L_{o}}{m_{o}} }$ (3)

By (2), we conclude that:

$v =v_{o}$

If we know that $v_{o} = 1\,\frac{m}{s}$ , then the new speed of the wave in the string is $v = 1\,\frac{m}{s}$ .

5 0

3 years ago

If two identical trees are cut down, one with a hand saw, and one with an electric saw...

nataly862011 [7]

The hand saw would involve more work because it takes more time and effort.

4 0

4 years ago

In which of these cases is NO work done on the football? A) You lift a football off the ground. B) You raise a football over you

inn [45]

I believe the answer is C.

8 0

3 years ago

Olivia is on a swing at the playground.

balu736 [363]

Olivia is on a swing at the playground. The kinetic energy is increasing and her potential energy decreasing at point X.

<h3>What is kinetic energy and potential energy?</h3>

The kinetic energy of an object is the ability to do work by virtue of its motion and potential energy is the ability to do work by virtue of its position.

At point W and Z, Olivia is at the maximum displacement from the mean position, where kinetic energy is zero and potential energy is maximum.

At point Y, it is approaching to increase its potential energy and decreasing kinetic energy. Opposite to this, at point X, kinetic energy is increasing and potential energy is decreasing.

Thus, the kinetic energy is increasing and her potential energy decreasing at point X.

Learn more about kinetic energy and potential energy.

brainly.com/question/15764612

#SPJ1

5 0

3 years ago

The x coordinate of an electron is measured with an uncertainty of 0.200 mm . What is vx, the x component of the electron's velo

Vikentia [17]

Answer:

Velocity of electron along x direction is 57.9 m/s

Explanation:

The uncertainty in x coordinate of electron, Δx = 0.200 mm = 0.2 x 10⁻³ m

Let vₓ be the x component of electrons velocity.

The uncertainty in x component of electrons momentum is:

Δpₓ = mΔvₓ

Here m is mass of the electron.

The uncertainty in velocity x component is 1% i.e. 0.01.

So, the above equation can be written as :

Δpₓ = 0.01mvₓ ....(1)

The minimum uncertainty principle is:

$\Delta x\Delta p_{x} = \frac{h}{2\pi }$ ....(2)

Here h is Planck's constant.

From equation (1) and (2),

$\Delta x\times0.01m v_{x} = \frac{h}{2\pi }$

Substitute 0.2 x 10⁻³ m for Δx, 9.1 x 10⁻³¹ kg for m and 6.626 x 10⁻³⁴ m²kg/s in the above equation.

$0.2\times10^{-3} \times0.01\times9.1\times10^{-31}\times v_{x} = \frac{6.626\times10^{-34} }{2\pi }$

vₓ = 57.9 m/s

8 0

3 years ago