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nadezda [96]
4 years ago
14

BRAINLIESTTTTT ASAP!!!

Mathematics
1 answer:
Alina [70]4 years ago
3 0
X^2 - 2x - 3 = 0
(x^2 - 2x +  ) - 3 -  = 0
(x^2 - 2x + 1) - 3 - 1 = 0
(x - 1)^2 - 4 = 0
(x - 1)^2 = 4
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20 pointsss :)
cluponka [151]
  • Answer:

180-93=87..... Exterior angles of a triangle

6 0
3 years ago
Find the sum of the first 8 terms in the geometric sequence: 1, 3, 9, 27,
Butoxors [25]

The sum of the first 8 items in the geometric sequence:1, 3, 9, 27, ...etc is 3280.

Step-by-step explanation:

The given is,

            sequence: 1,3,9,21,.. etc

Step:1

           The given is based on multiplication of 3 to previous number,

           ( x - previous number, next number = 3 × x )

            First term : 1

            Second term : 1 × 3 = 3

           Third term : 3 × 3 = 9

            Fourth term : 9 × 3 =27

            Fifth term : 27 × 3 = 81

            Sixth term : 81 × 3 = 243

            Seventh term : 243 × 3 = 729

            Eighth term : 729 × 3 = 2187

Step:2

            Sum of first 8 terms = 1 + 3 + 9 + 27 + 81 + 243 + 729 + 2187

                                              = 3280

            Sum of first 8 terms = 3280

Result:

           The sum of the first 8 items in the geometric sequence:1, 3, 9, 27, ...etc is 3280.

                                       

7 0
3 years ago
CLASS 6 MATHS!!!! HELP ME PLEASE!!!!!!!​
Elanso [62]

Step-by-step explanation:

\\ 20. \:  \: ( \frac{ - 3}{4} )(4\frac{1}{6} )

\\  =  \frac{ - 3}{4}  \times  \frac{25}{6}

\\  =  \frac{ - 25}{8}

\\  =  - 3.125

\\ 21. \:  \: ( - 3\frac{7}{8} )( - 5\frac{3}{4} )

\\  =  \frac{ - 31}{8}  \times  \frac{ - 23}{4}

\\  =  \frac{713}{32}

\\  = 22.28125

6 0
3 years ago
Consider the system of equations.
worty [1.4K]
Try to repost so somebody answer
6 0
3 years ago
A football quarterback enjoys practicing his long passes over 40 yards. He misses the first pass 40% of the time. When he misses
laila [671]

Answer:

Probability of missing two passes in a row is 0.08.

Step-by-step explanation:

Event E = A football player misses twice in a row.

P(E) = ?

Event X = Football player misses the first pass

P(X) = 0.4

Event Y = Football player misses just after he first miss

P(Y) = 0.2

Both the events are exclusive so the probability of occuring of these two events can be calculated by the formula:

P(E) = P(X).P(Y)

P(E) = 0.4*0.2

P(E) = 0.08

4 0
4 years ago
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