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tigry1 [53]
3 years ago
5

I will give brainleist! Please help on all it’s my homework i don’t know how to do

Mathematics
2 answers:
Len [333]3 years ago
6 0

Answer:

17) 3   18) 3

Step-by-step explanation:

AlexFokin [52]3 years ago
3 0

Answer:

17. C

18. C

Step-by-step explanation:

The greater the negative number, the less the number values. -10 is smaller than -8 because -10 is farther away from the number line to the left.

Go in terms of the tenths place. If its smaller than the number will be less than the bigger numbers. 0.227 is bigger than 0.18 because it has a 2 in the tenths place.

I hope this helped and if it did I would appreciate it if you marked me Brainliest. Thank you and have a nice day!

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Can you confirm is hypotenuse should be AC...

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4 years ago
Which best describes how to find an equation of the line shown?
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Slope is rise/ run and rise/run is y/x. c?
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4 years ago
Solve for x. x2−9=16 Enter the solutions for the equation in the boxes. x = ___ or x = ___
const2013 [10]

Answer:

x = 5 or x = -5

Step-by-step explanation:

x^2−9=16

Add 9 to both sides

x^2 = 25

√x^2 = √25

x = 5 or x = -5

6 0
4 years ago
Read 2 more answers
Plzzzz I NEED help with 9 and 10 plzzzzz
jeyben [28]

<u><em>Question 9:</em></u>

\frac{20*(5)}{50}                    Simplify what is in the parenthesis

\frac{100}{50}                        Multiply 20 to 5

2                                            Divide 50 to 100

<u><em>*(Answer)*=</em></u> 2  

<u><em>Question 10:</em></u>

5+(18) ÷ 6                Simplify what is in the parenthesis      

5+3                                         Divide 6 to 18

8                                              Add 5 to 3

<u><em>*(Answer)*=</em></u> 8

Hope this helps

User who answered: <u><em>BangtanBoyScouts</em></u>






4 0
4 years ago
3. Solve each of the following constant coefficient ordinary differential equations: (10 pts] a) y"+ 3y'- 28y = 0
eduard

Answer:

y(t) = C_1e^{4t} + C_2e^{-7t}

Step-by-step explanation:

We are given the following information in the question:

y''+3y'-28y = 0

This can be written as:

(D^2 + 3D - 28)y = 0

The auxiliary equation obtained is:

m^2+ 3m - 28 = 0\\ m^2 + 7m - 4m - 28 = 0\\m(m+7)-4(m+7)=0\\(m-4)(m+7)\\m = 4, m = -7

Thus, the general solution of the equation is:

y(t) = C_1e^{4t} + C_2e^{-7t}\\\text{where } C_1, C_2 \text{ are constants}

6 0
3 years ago
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