Ask question

Ask question

All categories

3 years ago

11

Solve the following systems of equations: 4x+5y=-4 4x+3y=12 X=? Y=?

2 answers:

Mrac [35]3 years ago

7 0

For this case we have the following system of equations:

$4x + 5y = -4\\4x + 3y = 12$

We multiply the second equation by -1:

$-4x-3y = -12$

We add the equations:

$4x-4x + 5y-3y = -4-12\\5y-3y = -4-12\\2y = -16\\y = \frac {-16} {2}\\y = -8$

We find the value of "x":

$4x = 12-3y\\x = \frac {12-3y} {4}\\x = \frac {12-3 (-8)} {4}\\x = \frac {12 + 24} {4}\\x = \frac {36} {4}\\x = 9$

Thus, the solution of the system is given by:

$(x, y) :( 9, -8)$

ANswer:

(9, -8)

Feliz [49]3 years ago

3 0

Answer:

x = 9 and y = -8

Step-by-step explanation:

It is given that,

4x + 5y = -4 ----(1)

4x + 3y = 12 -----(2)

<u>To find the value of x and y</u>

eq (1) - eq (2) ⇒

4x + 5y = -4 ----(1)

<u>4x + 3y = 12 -----(2)</u>

0 + 2y = -16

y = -16/2 = -8

Substitute the value of y in eq (1)

4x + 5y = -4 ----(1)

4x + 5*-8 = -4

4x - 40 = -4

4x = -4 + 40 = 36

x = 36/4 = 9

x = 9 and y = -8

You might be interested in

Please do the equation and cost for 15 people

Lunna [17]

Answer:

24

Step-by-step explanation:

Because the C represents the 4 let 24 represent the answer.

8 0

3 years ago

2 points) Sometimes a change of variable can be used to convert a differential equation y′=f(t,y) into a separable equation. One

Stells [14]

$y'=(t+y)^2-1$

Substitute $u=t+y$ , so that $u'=y'$ , and

$u'=u^2-1$

which is separable as

$\dfrac{u'}{u^2-1}=1$

Integrate both sides with respect to $t$ . For the integral on the left, first split into partial fractions:

$\dfrac{u'}2\left(\frac1{u-1}-\frac1{u+1}\right)=1$

$\displaystyle\int\frac{u'}2\left(\frac1{u-1}-\frac1{u+1}\right)\,\mathrm dt=\int\mathrm dt$

$\dfrac12(\ln|u-1|-\ln|u+1|)=t+C$

Solve for $u$ :

$\dfrac12\ln\left|\dfrac{u-1}{u+1}\right|=t+C$

$\ln\left|1-\dfrac2{u+1}\right|=2t+C$

$1-\dfrac2{u+1}=e^{2t+C}=Ce^{2t}$

$\dfrac2{u+1}=1-Ce^{2t}$

$\dfrac{u+1}2=\dfrac1{1-Ce^{2t}}$

$u=\dfrac2{1-Ce^{2t}}-1$

Replace $u$ and solve for $y$ :

$t+y=\dfrac2{1-Ce^{2t}}-1$

$y=\dfrac2{1-Ce^{2t}}-1-t$

Now use the given initial condition to solve for $C$ :

$y(3)=4\implies4=\dfrac2{1-Ce^6}-1-3\implies C=\dfrac3{4e^6}$

so that the particular solution is

$y=\dfrac2{1-\frac34e^{2t-6}}-1-t=\boxed{\dfrac8{4-3e^{2t-6}}-1-t}$

3 0

3 years ago

Find the interior angle sum for the following polygon

wolverine [178]

Answer:

1620°

Step-by-step explanation:

The figure is an 11-sided polygon and is called hendecagon

The interior angle sum:

180( n-2) n=11

=180(11-2)

=180(9)

=1620°

I hope this help you

5 0

3 years ago

Please help been stuck on this for 40 minutes

choli [55]

we have given y interms of x.

we have given that add 2 to x.

which means $y=x+2$

so we have $x=2 ,y=x+2=2+2=4$ .

so when x $=2 ,y=4$ .

$x=4,y=x+4=4+2=6.$ .

$y=x+2,y=6+2=8$ .

3 0

3 years ago

Read 2 more answers

The water level in a tank decreased 8 inches in 4 minutes. The tank drains at a steady rate. What is the change in the water lev

aalyn [17]

2 inches per minute 8÷4=2

3 0

4 years ago