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Answer:
- Constraints: x + y ≤ 250; 250x +400y ≤ 70000; x ≥ 0; y ≥ 0
- Objective formula: p = 45x +50y
- 200 YuuMi and 50 ZBox should be stocked
- maximum profit is $11,500
Step-by-step explanation:
Let x and y represent the numbers of YuuMi and ZBox consoles, respectively. The inventory cost must be at most 70,000, so that constraint is ...
250x +400y ≤ 70000
The number sold will be at most 250 units, so that constraint is ...
x + y ≤ 250
Additionally, we require x ≥ 0 and y ≥ 0.
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A profit of 295-250 = 45 is made on each YuuMi, and a profit of 450-400 = 50 is made on each ZBox. So, if we want to maximize profit, our objective function is ...
profit = 45x +50y
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A graph is shown in the attachment. The vertex of the feasible region that maximizes profit is (x, y) = (200, 50).
200 YuuMi and 50 ZBox consoles should be stocked to maximize profit. The maximum monthly profit is $11,500.
Answer:
It is a metaphor.
Step-by-step explanation:
Hope it helps
Your answer to the first one is incorrect.
We can cut the plan into two figures, a rectangle with side lengths of 4 cm and 5 cm and a rectangle with side lengths of 1 and 2 cm.
Perimeter of a Rectangle:
P = 2(l + w)
P = 2(4 + 5)
P = 2(9)
P = 18
Perimeter of a Rectangle:
P = 2(l + w)
P = 2(2 + 1)
P = 2(3)
P = 6
Add up the perimeters:
18 + 6 = 24
So the total perimeter is 24.
For the 2nd one, your answer is also incorrect.
We multiply 5 to the perimeter of the plans:
5 * 24 = 120
Not sure what the third one is asking.
For the fourth one we just multiply 'k' to the perimeter:
24 * k = 24k