Answer:
yes
Step-by-step explanation:
Answer:
1/12
Step-by-step explanation:
hope this helps you
Answer:
Step-by-step explanation:
We want to determine a 95% confidence interval for the mean mean test score of students.
Number of sample, n = 25
Mean, u = 81.5
Standard deviation, s = 10.2
For a confidence level of 95%, the corresponding z value is 1.96. This is determined from the normal distribution table.
We will apply the formula
Confidence interval
= mean ± z score ×standard deviation/√n
It becomes
81.5 ± 1.96 × 10.2/√25
= 81.5 ± 1.96/× 2.04
= 81.5 ± 3.9984
The lower end of the confidence interval is 81.5 - 3.9984 =77.5
The upper end of the confidence interval is 81.5 + 3.9984 = 85.5
Therefore, with 95% confidence interval, the mean test score of students is between 77.5 and 85.5
2*pi*radius2
the two after the radius means exponent.
so plug in the numbers: 2*3.14*9.9225= 62.3133
Answer:
y is the vertical axis. x is the horizontal axis. Replace any value in x to get your y value. The value you input as x is your x value. God this sounds confusing. I'd graph it for you but i don't know how to do that on Brainly.
Step-by-step explanation: