= (8 x 2) x (10^7 x 10^6)
= 16 x 10^13
= 1.6 x 10^14
answer is C
1.6 x 10^14
Given:
Vertices of a square are A(-4,6), B(5,6) C(4,-2), and D(-5,-2).
To find:
The intersection of the diagonals of square ABCD.
Solution:
We know that diagonals of a square always bisect each other. It means intersection of the diagonals of square is the midpoint of diagonals.
In the square ABCD, AC and BD are two diagonals. So, intersection of the diagonals is the midpoint of both AC and BD.
We can find midpoint of either AC or BD because both will result the same.
Midpoint of A(-4,6) and C(4,-2) is





Therefore, the intersection of the diagonals of square ABCD is (0,2).
Answer:
total cost = 5 + 2t
Step-by-step explanation:
Answer: 126 Degrees
Step-by-step explanation: Two angles that are supplementary always equal 180 degrees which means all you have to do is 180-54 and that is your answer. Plz mark Brainliest :).