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Komok [63]
3 years ago
12

PLEASE ANSWER

Mathematics
1 answer:
dalvyx [7]3 years ago
5 0
(0, 10)
(17, 0)
(0, -12)
(18, 0)
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The slope-point form of line:

y-y_1=m(x-x_1)\\\\m=\dfrac{y_2-y_1}{x_2-x_1}

We have the points (-9, 7) and (6, 2). Substitute:

m=\dfrac{2-7}{6-(-9)}=\dfrac{-5}{6+9}=-\dfrac{5}{15}=-\dfrac{1}{3}\\\\y-7=-\dfrac{1}{3}(x-(-9))\\\\\boxed{y-7=-\dfrac{1}{3}(x+9)}

The slope-intercept form of line:

y=mx+b.

We have the slope m:

y=-\dfrac{1}{3}x+b

Pu the coordinates of the point (6, 2) to the equation:

2=-\dfrac{1}{3}(6)+b

2=-2+b             <em>add 2 to both sides</em>

4=b\to b=4

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Answer:

13.62205 is your answer

Step-by-step explanation:

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