I need to know if this is right please help

Mathematics

1 answer:

8090 [49]3 years ago

6 0

Yes your right because
$- \frac{3}{4} equals \: - 0.75$
$- \frac{1}{4} = - 0.25$
$0$
$\frac{1}{4} = 0.25$
$\frac{1}{2} = 0.5$
thats least to greatest

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The formula for the area of a parallelogram is A = bh, where b is the base and h is the height. A parallelogram that is not draw

Bezzdna [24]

Answer:

Option 2) 2x3 – 6x2 – 14x + 24 square centimeters

Step-by-step explanation:

We know the Parallelogram Area is given by

$A=bh$ Eqn. (1)

where

$b$ : is the base

$h$ : is the height

We are also given that the base is

$b=2x^2+2x-6$

and the height is

$h=x-4$

So we can plug these two expressions in Eqn. (1), simplify and find our Area equation as follow:

$A=(2x^2+2x-6)(x-4)\\\\A=(2x^2)(x)+(2x)(x)-(6)(x)+(2x^2)(-4)+(2x)(-4)-(6)(-4)\\\\A=2x^3+2x^2-6x-8x^2-8x+24\\\\A=2x^3+2x^2-8x^2-6x-8x+24\\\\A=2x^3-6x^2-14x+24$

Which matches Option 2. from the available ones.

3 0

3 years ago

Read 2 more answers

WILL GIVE BRAINLIEST!!! Given tan(theta) = 4/3 and pi < theta < (3pi)/2, find cos(2theta).

babymother [125]

Answer: $\cos 2 \theta = \dfrac{-7}{25}$

Step-by-step explanation:

Given: $\tan \theta = \dfrac{4}{3}$ and $\pi < \theta< \dfrac{3\pi }{2}$

To find: $\cos 2 \theta$

Now as we know

$\cos 2x = \dfrac{1- \tan ^2 x}{1+ \tan ^2 x}$

So we have

$\cos 2 \theta = \dfrac{1-(\dfrac{4}{3} )^2}{1+(\dfrac{4}{3} )^2} \\\\\Rightarrow \cos 2 \theta = \dfrac{1- \dfrac{16}{9} }{1+ \dfrac{16}{9} } = \dfrac{\dfrac{9-16}{9} }{\dfrac{9+16}{9}} = \dfrac{-7}{25}$