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andrey2020 [161]
3 years ago
5

True or false? if the copyright date on the homepage is more than 1 year old, the website should always be considered unmaintain

ed.
Computers and Technology
1 answer:
san4es73 [151]3 years ago
7 0
I believe that the answer to the question provided above is  false, <span> if the copyright date on the homepage is more than 1 year old, the website should always be considered maintained.</span>
Hope my answer would be a great help for you.    If you have more questions feel free to ask here at Brainly.
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2. Use inheritance to create a hierarchy of Exception classes -- EndOfSentenceException, PunctuationException, and CommaExceptio
Lelechka [254]

Answer:

See explaination

Explanation:

EndOfSentenceException.java

//Create a class EndOfSentenceException that

//extends the Exception class.

class EndOfSentenceException extends Exception

{

//Construtor.

EndOfSentenceException(String str)

{

System.out.println(str);

}

}

CommaException.java

//Create a class CommaException that extends the class

//EndOfSentenceException.

class CommaException extends EndOfSentenceException

{

//Define the constructor of CommaException.

public CommaException(String str)

{

super(str);

}

}

PunctuationException.java

//Create a class PunctuationException that extends the class

//EndOfSentenceException.

class PunctuationException extends EndOfSentenceException

{

//Constructor.

public PunctuationException(String str)

{

super(str);

}

}

Driver.java

//Include the header file.

import java.util.Scanner;

//Define the class Driver to check the sentence.

public class Driver {

//Define the function to check the sentence exceptions.

public String checkSentence(String str)

throws EndOfSentenceException

{

//Check the sentence ends with full stop,

//exclamation mark

//and question mark.

if(!(str.endsWith(".")) && !(str.endsWith("!"))

&& !(str.endsWith("?")))

{

//Check the sentence is ending with comma.

if(str.endsWith(","))

{

//Throw the CommaException.

throw new CommaException("You can't "

+ "end a sentence in a comma.");

}

//Otherwise.

else

{

//Throw PunctuationException.

throw new PunctuationException("The sentence "

+ "does not end correctly.");

}

}

//If the above conditions fails then

//return this message to the main function.

return "The sentence ends correctly.";

}

//Define the main function.

public static void main(String[] args)

{

//Create an object of Scanner

Scanner object = new Scanner(System.in);

//Prompt the user to enter the sentence.

System.out.println("Enter the sentence:");

String sentence=object.nextLine();

//Begin the try block.

try {

//Call the Driver's check function.

System.out.println(new

Driver().checkSentence(sentence));

}

//The catch block to catch the exception.

catch (EndOfSentenceException e)

{}

}

}

5 0
3 years ago
What is theory of knowledge?​
Karolina [17]
Theory of knowledge (TOK) plays a special role in the International Baccalaureate® (IB) Diploma Programme (DP), by providing an opportunity for students to reflect on the nature of knowledge, and on how we know what we claim to know.
4 0
3 years ago
Hdhdhrhdh you are not the intended recipient. xmp-qite-xsy.​
Aleks04 [339]

Answer:

ummmm... okay

Explanation:

3 0
3 years ago
What is the best anime that you like the most (give me 3 plz)
Dmitry [639]

Answer:

The rising of shied hero, last hope, and dragon pilot.

4 0
3 years ago
Read 2 more answers
Write a program for determining if a year is a leap year. In the Gregorian calendar system you can check if it is a leaper if it
SOVA2 [1]

Answer:

def leap_year_check(year):

return if int(year) % 4 == 0 and (int(year) % 100 != 0 or int(year) % 400 == 0)

Explanation:

The function is named leap_year_check and takes in an argument which is the year which we wish to determine if it's a new year or not.

int ensures the argument is read as an integer and not a float.

The % obtains the value of the remainder after a division exercise. A remainder of 0 means number is divisible by the quotient and a remainder other wise means it is not divisible by the quotient.

If the conditions is met, that is, (the first condition is true and either the second or Third condition is true)

the function leap_year_check returns a boolean ; true and false if otherwise.

8 0
3 years ago
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