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3 years ago

6

Two long jumpers competed in a world-class track meet. The first athlete jumped a distance of 28.65 feet, and the second athlete

reached a distance of 24.25 feet. The first athlete jumped feet farther than the second athlete.

2 answers:

Elena-2011 [213]3 years ago

4 0

4.40 feet farther than the second athlete

Leona [35]3 years ago

3 0

4.40 feet farther than the second athlete

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What are the values of the7's in 17,372

vitfil [10]

Hi there Alley!

I'll be answering your question :)
So, your question asks you to state the value of '7' in 17,372. We can answer this by looking at the number and looking for the number 7; '7' is in the thousand column. Thus, the value of 7 in 17,372 is:

7000 Thousand <--- The Answer

Hope this Helped ;)

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3 years ago

Help please, question attached

Alexxandr [17]

Answer:

C. x = 8

Step-by-step explanation:

We know that x · x · x is equal to 512. We know it cannot be negative because then the 512 would be negative. -2 x -2 x -2 is -8. -2 x -2 is 4. We know it cannot be B x = -6 or D. x = -8.

Let's multiply 6 x 6 x 6.

36 x 6 = 216.

Let's multiply 8 x 8 x 8.

64 x 8 = 512

The answer would be C. x = 8.

I hope that this helps! :)

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3 years ago

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sales at flower shop were $814 this week. this is $131 less than the sales last week. what were last weeks sales?

sertanlavr [38]

Answer: The sales last were $945.

Step-by-step explanation: The sales this week are $945 and they are $131 less than that of last week. This means that they have reduce by $131,therefore we have to add the two values

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3 years ago

A box of candy hearts contains 52 hearts, of which 19 are white, 10 are tan, 7 are pink, 3 are purple, 5 are yellow, 2 are orang

laiz [17]

<u>Answer-</u>

a. Probability that three of the candies are white = 0.29

b. Probability that three are white, 2 are tan, 1 is pink, 1 is yellow, and 2 are green = 0.006

<u>Solution-</u>

There are 19 white candies, out off which we have to choose 3.

The number of ways we can do the same process =

$\binom{19}{3} = \frac{19!}{3!16!} = 969$

As we have to draw total of 9 candies, after 3 white candies we left with 9-3 = 6, candies. And those 6 candies have to be selected from 52-19 = 33 candies, (as we are drawing candies other than white, so it is subtracted)

And this process can be done in,

$\binom{33}{6} = \frac{33!}{6!27!} =1107568$

So total number of selection = (969)×(1107568) = 1073233392

Drawing 9 candies out of 52 candies,

$\binom{52}{9} = \frac{52!}{9!43!} = 3679075400$

∴P(3 white candies) = $\frac{1073233392}{3679075400} =0.29$

Total number of ways of selecting 3 whites, 2 are tans, 1 is pink, 1 is yellow, and 2 are greens is,

$\binom{19}{3} \binom{10}{2} \binom{7}{1} \binom{5}{1} \binom{6}{2}$

$=(\frac{19!}{3!16!}) (\frac{10!}{2!8!}) (\frac{7!}{1!6}) (\frac{5!}{1!4!}) (\frac{6!}{2!4!})$

$=(969)(45)(7)(5)(15)=22892625$

Total number of selection = 3 whites + 2 are tans + 1 is pink + 1 is yellow + 2 greens = 9 candies out of 52 candies is,

$\binom{52}{9}=\frac{52!}{9!43!} =3679075400$

∴ P( 3 whites, 2 are tans, 1 is pink, 1 is yellow, 2 greens) =

$\frac{22892625}{3679075400} = 0.006$

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3 years ago

What is the value of 12.5(- 2¾)

mote1985 [20]

The answer is -34.375

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3 years ago

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