Answer:
Problem 1. <em>(19/2)b + 15</em>
Problem 2. <em>3/16</em>
Step-by-step explanation:
Question number 1
5/8 (16b+24) -1/2b =
= (5/8) * (16/1) * b + (5/8) * 24 - (1/2)b
= 10b + 15 - (1/2)b
= (20/2)b - (1/2)b + 15
= (19/2)b + 15
Question number 2
3/4 (16/64 + 12a) -9a =
= (3/4) * (16/64) + (3/4) * 12a - 9a
= (3 * 16)(4 * 64) + (3/4) * (12/1) * a - 9a
= (3 * 1)(4 * 4) + (3 * 12)/(4 * 1) * a - 9a
= 3/16 + (3 * 3)/(1 * 1) * a - 9a
= 3/16 + 9a - 9a
= 3/16
Answer:
1860
Step-by-step explanation:
1875-15 = 1860
Answer:
2. n = 11
4. g = -2
6. t = 21
8. n = 4
10. y = -1
Step-by-step explanation:
2. 63 = -3(1 - 2n)
Dividing both the side by negative 3 we get

4. -g + 2(3 + g) = -4(g + 1)
First we will open the bracket by distributive property A( B +C) = AB + AC

6.-3(t +5 ) + (4t + 2) = 8
Using distributive property A( B +C) = AB + AC we get

8. -8 - n = -3(2n -4)
Using distributive property A( B +C) = AB + AC we get

10. -4( 2 - y) + 3y = 3(y - 4)
Using distributive property A( B +C) = AB + AC we get

You can use desmos! and to solve you find the point(s) where they overlap