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Stella [2.4K]
3 years ago
8

PLEASE PLEASE HELP ME WITH THIS QUESTION

Mathematics
1 answer:
Ad libitum [116K]3 years ago
8 0

Answer:

The last one

Step-by-step explanation:

1/256 can only be a non fraction is the exponent is negative.  but since the t is not also in the denominators the original two exponents must be negative so they times to a positive so:

(4t^-4) ^-7

(4^-7) (t^-4×-7)

(1/4^7) (t^28)

1/256 t^28

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URGENT!! The difference between the roots of the quadratic equation x2−12x+q=0 is 2. Find q
Sedaia [141]

Answer:

q=35

Step-by-step explanation:

x2 - 12x + q = 0

Let the two roots be r and r+2.

Factor the quadratic expression:

(x - r)[x - (r + 2)] = 0

Expand, simplify, group like terms, and get

x2 - 2(r + 1)x + r(r + 2) = 0

Compare to

x2 - 12x + q = 0

and set equal the coefficients of like terms:

Coefficient of x:

-2(r + 1) = -12 ⇒ r + 1 = 6 ⇒ r = 5

(Then the other root is r + 2 = 5 + 2 = 7)

Constant term:

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q = 35

Test the solution:

(x - 5)(x - 7) = x2 - 12x + 35

With two roots differing by 2, you get an equation of the form

x2 - 12x + q = 0

with q = 35.

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3 years ago
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Please answer quickly
Marta_Voda [28]

Answer:

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Step-by-step explanation:

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