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3 years ago

Use the Intermediate Value Theorem to show that the polynomial has a real zero between -4 and -1

Mathematics

1 answer:

hjlf3 years ago

8 0

The answer is A
F (-4)=-23 < 0
F (-1)=16> 0

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Naya [18.7K]

Using the z-distribution, it is found that the lower bound of the 99% confidence interval is given by:

d. 68.39%.

<h3>What is a confidence interval of proportions?</h3>

A confidence interval of proportions is given by:

$\pi \pm z\sqrt{\frac{\pi(1-\pi)}{n}}$

In which:

$\pi$ is the sample proportion.

z is the critical value.

n is the sample size.

In this problem, we have a 99% confidence level, hence $\alpha = 0.99$ , z is the value of Z that has a p-value of $\frac{1+0.99}{2} = 0.995$ , so the critical value is z = 2.575.

The sample size and estimate are given by:

$n = 2002, \pi = 0.71$

Hence, the lower bound is given by:

$\pi - z\sqrt{\frac{\pi(1-\pi)}{n}} = 0.71 - 2.575\sqrt{\frac{0.71(0.29)}{2002}} = 0.6839$

Hence the lower bound is of 68.39%, which means that option D is correct.

More can be learned about the z-distribution at brainly.com/question/25890103

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2 years ago

BRAINLIEST MATH okurttttt

Zepler [3.9K]

In the given question, $\sqrt{x-1}$ is shifted one unit to the right of $\sqrt{x}$

So, Option C is correct.

Step-by-step explanation:

The parent function is $\sqrt{x}$ and transformed function is $\sqrt{x-1}$

So, Parent Function: $\sqrt{x}$

Transformed Function: $\sqrt{x-1}$

If transformed function is of type: g(x) = f(x-h), then the graph is shifted to right h units.

So, In the given question, $\sqrt{x-1}$ is shifted one unit to the right of $\sqrt{x}$

So, Option C is correct.

Keywords: Transformations

Learn more about Transformations at:

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3 years ago

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2 years ago

What is the product of 34.2 and 1.2

sertanlavr [38]

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3 years ago

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How do u solve xk = w - v for x

Wewaii [24]

Answer:

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