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3 years ago

8

What is the radius of a circle if its area is 120 in2? (Round your answer to the nearest hundredth of an inch)

1 answer:

asambeis [7]3 years ago

8 0

Answer:

6.18

Step-by-step explanation:

120/3.14, square root then round

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Thru (4,0) parallel to y=1/2x+5

Ne4ueva [31]

Paralell has same slope
y=mx+b
m=slope
y=1/2x+b
find b
(x,y)
(4,0)

x=4
y=0
0=1/2(4)+b
0=2+b
minus 2 both sides
-2=b

the equaiton is
y=1/2x-2
or
x-2y=4

7 0

2 years ago

Fifty people were surveyed about their favorite flavor of frozen yogurt. The results of the survey are displayed in the circle g

Ksju [112]

The answer is 2. This is because 2 = 4% of 50.

You can think of it like this:

4 is 4% of 100.

50 is half of 100.

Therefore, 4% of 50 is HALF of 4% of 100.

4 divided by 2 = 2

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3 years ago

M angle PQS= 3x; m angle SQR=5x-20 <br> Find x

Dahasolnce [82]

Let as consider the complete ques is : Ray QS bisects ∠PQR. Solve for x and find m∠PQR. m∠PQS = 3x ; m∠SQR = 5x-20.

Given:

Ray QS bisects ∠PQR.

m∠PQS = 3x

m∠SQR = 5x-20

To find:

The value of x and m∠PQR

Solution:

Ray QS bisects ∠PQR. So,

$m\angle PQS=m\angle SQR$

$3x=5x-20$

$3x-5x=-20$

$-2x=-20$

$x=10$

The value of x is 10.

Now,

$m\angle PQR=m\angle PQS+m\angle SQR$

$m\angle PQR=3x+5x-20$

$m\angle PQR=8x-20$

Put x=10,

$m\angle PQR=8(10)-20$

$m\angle PQR=80-20$

$m\angle PQR=60$

Therefore, the m∠PQR is 60 degrees.

5 0

3 years ago

Solve 4x−9y=13 for y.

Irina18 [472]

Answer:

$y = - \frac{13}{9} + \frac{4}{9} x$

Step-by-step explanation:

$4x - 9y = 13$

$4x - 9y - 4x = 13 - 4x$

$- 9y = 13 - 4x$

$y = 9y \div (9) = (13 - 4x) \div ( - 9)$

$y = (13 - 4x) \div( - 9)$

$y = 13 \div ( - 9) - 4x \div ( - 9)$

$y = - 13 \div 9 - 4x \div ( - 9)$

$y = - \frac{13}{9} - 4x \div ( - 9)$

$y = - \frac{13}{9} + 4x \div 9$

$\boxed{\green{y = - \frac{13}{9} + \frac{4}{9} x, x E R}}$

8 0

3 years ago

Find the value of r that makes m<br> II<br> n.<br> m<br> n<br> (180 - x) º<br> xº

lys-0071 [83]

Answer:

(180-x)⁰ or it might also be X⁰

5 0

2 years ago