M2 = 272 182 – 2(27)(18)cos(28°) m2 = 729 324 – (972)cos(28°) m2 = 1053 – (972)cos(28°) to the nearest whole number, the value o
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Let's find out the gradient (Slope " m ") of line q ;
Now, since we already know the gradient let's find of the equation of line by using its Slope and one of the points using point slope form of line :
Now, plug in the value of gradient ~
here we can clearly observe that, the Area under the curve can easily be represented as :
Since, all the values of y that lies in the shaded region is smaller than the actual value of y for the corresponding values of x in the equation of line q