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KATRIN_1 [288]
3 years ago
11

Help me please Algebra two!

Mathematics
1 answer:
KatRina [158]3 years ago
8 0

Answer:

Zeros: -3 odd mult.; 0 odd mult.; 2 odd mult.

Positive leading coefficient

Odd degree likely 3

Step-by-step explanation:

A polynomial graph has several features we look for to determine the equations.

  • The zeros of the function are the x-intercepts. If the x-intercepts touch but do not cross then the intercepts have an even multiplicity like 2, 4, 6, etc. If the x-intercepts cross over then they have an odd multiplicity.
  • Degree is the exponent or multiplicity of each zero. Therefore if we know the multiplicity of each zero we can add them together to find or make an educated guess for the degree of the entire polynomial.
  • The shape of the graph tells us what type of polynomial. Odd degrees have a backwards S shape. Even degrees have a W shape. The shape can even tell us the if the equation has a positive or negative leading coefficient. Upside down W or an M shape is negative. While a sideways S shape is negative.
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Gretchen made a paper cone to hold a gift for a friend. The paper cone was 14 inches high and had a
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Answer:

268.0 in²

Step-by-step explanation:

refer to attached graphic as reference

volume of cone, V = (1/3) πr²h

in our case, we are given r = 4" and h = 16"

substituting this into equation:

V = (1/3) πr²h

=  (1/3) ·(3.14) · (4)²· (16)

= 267.94667 in²

= 268.0 in² (nearest tenth)

8 0
2 years ago
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Keran works for 85 hours throughout a two-week period. She earns 1,891.25 throughout this period. How much does Karen earn for e
meriva

Answer:

178 is your answer I'm pretty sure

4 0
3 years ago
In a direct variation, the ratio of y -values to x -values is equal to a constant.
liberstina [14]

Answer:

True

Step-by-step explanation:

The equation of direct variation is

y = kx ← k is the constant of variation

To find k divide both sides by x

\frac{y}{x} = k

That is the constant is the ratio of y- values to x- values

3 0
3 years ago
Jennifer is ordering cake for her wedding reception. If one cake feed 18 people, how many cakes does she need to order for 150 p
ehidna [41]

Answer:

8 1/3 cakes

Step-by-step explanation:

Step 1:

1 : 18        Ratio

Step 2:

1 : 18 = x : 150       Proportion

Step 3:

150 = 18x       Multiply

Step 4:

150 ÷ 18 = x     Divide

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x = 8 1/3  

Hope This Helps :)

8 0
3 years ago
The mean of a population is 74 and the standard deviation is 15. The shape of the population is unknown. Determine the probabili
Lena [83]

Answer:

a) 0.0548 = 5.48% probability of a random sample of size 36 yielding a sample mean of 78 or more.

b) 0.9858 = 98.58% probability of a random sample of size 150 yielding a sample mean of between 71 and 77.

c) 0.5793 = 57.93% probability of a random sample of size 219 yielding a sample mean of less than 74.2

Step-by-step explanation:

To solve this question, we need to understand the normal probability distribution and the central limit theorem.

Normal Probability Distribution:

Problems of normal distributions can be solved using the z-score formula.

In a set with mean \mu and standard deviation \sigma, the z-score of a measure X is given by:

Z = \frac{X - \mu}{\sigma}

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the p-value, we get the probability that the value of the measure is greater than X.

Central Limit Theorem

The Central Limit Theorem estabilishes that, for a normally distributed random variable X, with mean \mu and standard deviation \sigma, the sampling distribution of the sample means with size n can be approximated to a normal distribution with mean \mu and standard deviation s = \frac{\sigma}{\sqrt{n}}.

For a skewed variable, the Central Limit Theorem can also be applied, as long as n is at least 30.

The mean of a population is 74 and the standard deviation is 15.

This means that \mu = 74, \sigma = 15

Question a:

Sample of 36 means that n = 36, s = \frac{15}{\sqrt{36}} = 2.5

This probability is 1 subtracted by the pvalue of Z when X = 78. So

Z = \frac{X - \mu}{\sigma}

By the Central Limit Theorem

Z = \frac{X - \mu}{s}

Z = \frac{78 - 74}{2.5}

Z = 1.6

Z = 1.6 has a pvalue of 0.9452

1 - 0.9452 = 0.0548

0.0548 = 5.48% probability of a random sample of size 36 yielding a sample mean of 78 or more.

Question b:

Sample of 150 means that n = 150, s = \frac{15}{\sqrt{150}} = 1.2247

This probability is the pvalue of Z when X = 77 subtracted by the pvalue of Z when X = 71. So

X = 77

Z = \frac{X - \mu}{s}

Z = \frac{77 - 74}{1.2274}

Z = 2.45

Z = 2.45 has a pvalue of 0.9929

X = 71

Z = \frac{X - \mu}{s}

Z = \frac{71 - 74}{1.2274}

Z = -2.45

Z = -2.45 has a pvalue of 0.0071

0.9929 - 0.0071 = 0.9858

0.9858 = 98.58% probability of a random sample of size 150 yielding a sample mean of between 71 and 77.

c. A random sample of size 219 yielding a sample mean of less than 74.2

Sample size of 219 means that n = 219, s = \frac{15}{\sqrt{219}} = 1.0136

This probability is the pvalue of Z when X = 74.2. So

Z = \frac{X - \mu}{s}

Z = \frac{74.2 - 74}{1.0136}

Z = 0.2

Z = 0.2 has a pvalue of 0.5793

0.5793 = 57.93% probability of a random sample of size 219 yielding a sample mean of less than 74.2

5 0
3 years ago
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