Selecting 5 students to participate in a math contest would require combinations.
<u>SOLUTION:
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given that, Selecting 5 students to participate in a math contest would require the calculating of a permutation or combination?
So, we need to differentiate between permutations and combinations.
Permutations - In mathematics, permutation is the act of arranging the members of a set into a sequence or order
Combinations - In mathematics, a combination is a selection of items from a collection, such that the order of selection does not matter.
So, now, for our math test, we just require students but not in an order nor with arrangements.
Hence, selecting 5 students to participate in a math contest would require combinations.
Answer:
Looks like the slope is -(1/2) and the equation is y= -(1/2)x + 1
Answer:
a: 0.08, or 8% chance he wins all 3
b: 0.42, or 42% chance he wins 2
Step-by-step explanation:
P(win A) = 0.8
P(lose A) = 0.2
P(win B) = 0.5
P(lose B) = 0.5
P(win C) = 0.2
P(lose C) = 0.8
The situations are independent, so we multiply probabilities together.
To win all 3: P(win A)*P(win B)*P(win C) = 0.8*0.5*.02 = 0.08
To win 2 of the 3 there are 3 ways to do this. We add up the probabilities of the 3 situations...
P(win A)*P(win B)*(lose C) = 0.8*0.5*0.8 = 0.32
P(win A)*P(lose B)*P(win C) = 0.8*0.5*0.2 = 0.08
P(lose A)*P(win B)*P(win C) = 0.2*0.5*.02 = 0.02
0.32 + 0.08 + 0.02 = 0.42
Answer:
She can buy 6
Step-by-step explanation:
4=36
1=9
54/9=6
3x+5-13x = 25
Subtract 13x from 3x
5 - 10x = 25
Subtract 5 from both sides
-10x = 20
Divide -10 on both sides so that the only thing remaining on the left side is the variable x.
Final Answer: -2
