All categories

3 years ago

Determine the intercepts of the line that correspond to the following table of values

Mathematics

1 answer:

almond37 [142]3 years ago

7 0

Find the equation

alrighty, the slope is rise/run

from (21,-3) to (28,-1)
rise is from -3 to -1 or a rise of 2
run is form 21 to 28 or a run of 7

so slope is 2/7

y=2/7x+b
find b which is the y intercept
alirhgty
use (21,-3)
x=21 and y=-3
-3=(2/7)(21)+b
-3=42/7+b
-3=6+b
-9=b

y=2/7x-9

the y intercept is (0,-9
the x intercept is where y=0

0=2/7x-9
9=2/7x
63/2=x

x intercept is (63/2,0) or (31.5,0)
y intercept is (0,-9)

You might be interested in

Solve. 4x−y−2z=−8 −2x+4z=−4 x+2y=6 Enter your answer, in the form (x,y,z), in the boxes in simplest terms. x= y= z=

ladessa [460]

Answer:

(-2, 4, -2)

x=-2, y=4, z=-2.

Step-by-step explanation:

So we have the three equations:

$4x-y-2z=-8\\-2x+4z=-4\\x+2y=6$

And we want to find the value of each variable.

To solve this system, first look at it and consider what you should try to do.

So we can see that the second and third equations both have an x.

Therefore, we can isolate the variables for the second and third equation and then substitute them into the first equation to make the first equation all xs.

Therefore, let's first isolate the variable in the second and third equation.

Second Equation:

$-2x+4z=-4$

First, divide everything by -2 to simplify things:

$x-2z=2$

Subtract x from both sides. The xs on the left cancel:

$(x-2z)-x=2-x\\-2z=2-x$

Now, divide everything by -2 to isolate the z:

$z=-\frac{2-x}{2}$

So we've isolated the z variable. Now, do the same to the y variable in the third equation:

$x+2y=6$

Subtract x from both sides:

$2y=6-x$

Divide both sides by 2:

$y=\frac{6-x}{2}$

Now that we've isolated the y and z variables, plug them back into the first equation. Therefore:

$4x-y-2z=-8\\4x-(\frac{6-x}{2})-2(-\frac{2-x}{2})=-8$

Distribute the third term. The -2s cancel out:

$4x-(\frac{6-x}{2})+(2-x)=-8$

Since there is still a fraction, multiply everything by 2 to remove it:

$2(4x-(\frac{6-x}{2})+(2-x))=2(-8)$

Distribute:

$8x-(6-x)+2(2-x)=-16\\8x-6+x+4-2x=-16$

Combine like terms:

$8x+x-2x-6+4=-16\\7x-2=-16$

Add 2 to both sides:

$7x=-14$

Divide both sides by 7:

$(7x)/7=(-14)/7\\x=-2$

Therefore, x is -2.

Now, plug this back into the second and third simplified equations to get the other values.

Second equation:

$z=-\frac{2-x}{2}\\ z=-\frac{2-(-2)}{2}\\z=-\frac{4}{2}\\z=-2$

Third equation:

$y=\frac{6-x}{2}\\y=\frac{6-(-2)}{2}\\y=\frac{8}{2}\\y=4$

Therefore, the solution is (-2, 4, -2)

3 0

3 years ago

Read 2 more answers

A. For 3 days in July the temperatures

ASHA 777 [7]

la temperatura promedio fue de 103°

4 0

3 years ago

What is 3x^2-2n-5=0 please help me!!!

expeople1 [14]

The answer to your question is:
It is a quadratic equation in 'x', with 'n' mistakenly typed in the second term..

Although you didn't ask for the solutions to the equation, I'm already here
so I might as well go through it and find them:

3x² - 2x - 5 = 0

In terms of the generic quadratic formula:
A = 3
B = -2
C = -5

Plug those into the quadratic formula, and you discover that

x = -1
and
x = ⁵/₃

7 0

3 years ago

Read 2 more answers

Find the factorization of the polynomial

makvit [3.9K]

There is only one real root, at x=-2, so the polynomial describing this parabola has factors of (x+2) with multiplicity 2. The y-intercept tells you the vertical stretch is 1.

The factorization is y = (x +2)².

6 0

3 years ago

How do i multiply negative exponents

katrin2010 [14]

You add the exponents together when multiplying

4 0

3 years ago

Read 2 more answers