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SpyIntel [72]
3 years ago
10

What is the reflection image of (5,-3) across the y-axis

Mathematics
2 answers:
Pepsi [2]3 years ago
8 0
I believe the answer is (-5,-3) because they are both equidistant from the y axis


Rina8888 [55]3 years ago
7 0
The reflection will be (-5,-3)
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Solve for the missing side round to the nearest 10th (look at image)
SIZIF [17.4K]

Answer:

14.3

Step-by-step explanation:

Since this is a right triangle, we can use the Pythagorean theorem

a^2 + b^2 = c^2   where a and b are the legs and c is the hypotenuse

14^2 + 3^2 = c^2

196 + 9 = c^2

205 = c^2

Take the square root of each side

sqrt(205) = sqrt(c^2)

14.31782106 = c

Rounding to the nearest tenth

14.3 = c

3 0
2 years ago
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Find the area of the trapezoid. A. 675 ft2 B. 337.5 ft2 C. 187.5 ft2 D. 150 ft2
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If parallelogram ABCD was reflected over the y-axis, reflected over the x-axis, and rotated 180°, where would point A' lie?
LuckyWell [14K]
D (-4 , -1)
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6 0
3 years ago
5.36 - 0.78 =<br><br> 4.58<br> 5.37<br> 4.38<br> 5.48
Daniel [21]
The answer to this is 4.58
6 0
3 years ago
On the day that Ramon is born, his grandfather deposited $5000 for him in a certificate of deposit paying 10% interest compounde
kkurt [141]

The time required to get a total amount of $1,000,000.00 with compounded interest on a principal of $5,000.00 at an interest rate of 10% per year and compounded 1 times per year is 55.59 years.

<h3>Given data</h3>

Principal = $5,000

Rate = 10%

Final Amount A= $1,000,000

Time = ?

First, convert R as a percent to r as a decimal

r = R/100

r = 10/100

r = 0.1 per year,

Then, solve the equation for t

t = ln(A/P) / n[ln(1 + r/n)]

t = ln(1,000,000.00/5,000.00) / ( 1 × [ln(1 + 0.1/1)] )

t = ln(1,000,000.00/5,000.00) / ( 1 × [ln(1 + 0.1)] )

t = 55.59 years

(about 55 years 7 months)

Learn more about compounding interest at:

brainly.com/question/1570054

4 0
2 years ago
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