For a vertical projectile, the equation of motion is expressed h(t)=g+bt+c, where g is gravity, b is the initial upward velocity, and c is the starting height. The maxima of this equation is given by -b/2g, which in this case would be -56/-32, or 1.75 seconds after launch
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<span>here is what i get :
x/3+11-(1/15)=0 </span>
Answer:
2 is 17.5
Step-by-step explanation:
bc the half of 4 is 2 since 4 is 35 we have to find the half of 35 and how we do that is by dividing it by 2.
35%2=17.5 so 2 is equal 17.5 so <2 is 17.5
