Luckily for us, the diagram already divided this figure into separate polygons. What I will be explaining is basically the addition of the areas of all the separate polygons. The area of the uppermost triangle is:
1/2 x b x h
= 1/2 x 20 x 8
(the base is 20, because in a parallelogram, opposite sides are congruent)
=10 x 8
= 80 in. squared
The next polygon we will be taking the area of is the parallelogram with the base length of 20 and the height of 16.
Area = b x h
= 20 x 16
= 320 in. squared
Now all we have left to do is add the two areas to obtain the total area.
Total Area = 320 + 80 = 400 in. squared
Answer:
Explanation:
3 + 2x - y = 0
Or 2x - y = -3 (1)
-3-7y = 10x
Or -10x - 7y = 3 (2)
2x - y = -3 (1)
-10x - 7y = 3 (2)
———————
Multiply 5 to (1)
5(2x - y = -3)
-10x - 7y = 3
———————
10x - 5y = -15
-10x - 7y = 3
———————
-12y = -12
y = -12/-12
y = 1
Plug y value in (1)
2x - 1 = -3
2x = -3 + 1
2x = -2
x = -2/2 = -1
Therefore, x = -1 and y = 1
Answer:
$62
Step-by-step explanation:
hope this helped!
p.s it would be cool if you gave me brainliest.
First we can find the perimeter of the given rectangle
P=2L+2W (L=length and W=width)
P=2*3+2*4
P=6+8
P=14
So now we want to come up with a different combination of numbers that would give up a perimeter of 14. We know that 14 is divisible by 2 so let's make out width 2. If we plug in 2 as the width and 14 as the perimeters, we can solve for length
14=2L+2*2
14=2L+4
10=2L (subtract 4 from both sides)
L=5
So the dimensions are 5 units and 2 units
Hope this helps!
