Answer:
Step-by-step explanation:
Number of electronic systems = 6
(a) Number of defected systems = 2
Probability of getting at least one system is defective
1 defective and 1 non defective + 2 defective
= (2 C 1 ) x (4 C 1) + (2 C 2) / (6 C 2)
= 3 / 5
(b) four defective
Probability of getting at least one system is defective
2 defective and 2 non defective + 3 defective and 1 non defective + 4 defective
= (4 C 2 ) x (2 C 2) + (4 C 3 )(2 C 1) + (4 C 4) / (6 C 4)
= 1
2% of 144.4 would be 2.888 repeating of course
Answer:
GCF = 17
Step-by-step explanation:
For the values 34, 85
Solution by Factorization:
The factors of 34 are: 1, 2, 17, 34
The factors of 85 are: 1, 5, 17, 85
Then the greatest common factor is 17.
Answer:
Idk
Step-by-step explanation: