Given a plane:
normal vector <2,4,-3>
passes through point (-1,3,5)
The equation of the plane is
Π : 2(x-(-1))+4(y-3)-3(z-5)=0
expand and simplify
Π : 2x+4y-3z+5=0
S2= 864/6
s = = 12 cm
p = 4/3 x 12 = 16 cm
t = 2/4 x 16 = 8 cm
l= 3/4x 16 = 12 cm
lp= 2 (pl+pt+lt)
= 2 (16 x 12 + 16 x 8 + 12 x8)
= 2 (192+128+96) = 832cm²
Answer:
Breadth or width = 4
Step-by-step explanation:
Givens
Area = 200 cm^2
L = 50 cm
w = ?
Formula
A = L*w
Solution
200 = 50 * w Divide by 50
200 / 50 = w
w = 4
