Question

Complete the steps to factor 56x2 – 8x – 7x + 1 by grouping.

Answer 1

The factorization of the polynomial $56x^2-8x-7x+1$ is $(8x-1)(7x-1)$

Step-by-step explanation:

We need to Complete the steps to factor $56x^2-8x-7x+1$ by grouping.

After grouping:

$(56x^2-8x) + (-7x + 1)$

Factor the GCF from each group.

$8x(7x-1)-1(7x-1)$

Use the distributive property.

$(8x-1)(7x-1)$

So, the factorization of the polynomial $56x^2-8x-7x+1$ is $(8x-1)(7x-1)$

Keywords: factorization by grouping

Learn more about factorization by grouping at:

• brainly.com/question/1464739
• brainly.com/question/2568692
• brainly.com/question/10771256

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Answer 2

Answer:(8x-1)(7x-1) The question leaves you with the partially factored equation: 8x(7x-1) - 1(7x-1) look at the partially factored equation, you'll see that both terms have (7x-1) as one of their factors. take that (7x-1) as a factor and divide both terms by (7x-1), giving you (8x(7x-1) - 1(7x-1)) / (7x-1) The (7x-1) factors cancel out, leaving you with (8x - 1) So your 2 factors are (7x-1) and (8x-1). Looking at the available options, the only correct one is (8x-1)(7x-1)