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3 years ago

Miranda enlarged a picture twice as shown below, each time using a scale factor of 3.

Mathematics

2 answers:

kobusy [5.1K]3 years ago

5 0

<h2>Answer: B, C, D</h2><h2 /><h2>Step-by-step explanation:</h2><h2>I did the test on E d g e n u i t y</h2>

Luda [366]3 years ago

4 0

Answer:

B, C, E are true

Step-by-step explanation:

A = l*w

The original rectangle is 6 by 4 with A = 24

The 1st enlargement = 6*3 by 4*3

18 by 12 with A = 216

The second enlargement is 18*3 by 12*3

54 by36 with A =1944

A.The area of the first enlargement is 72 square inches.

False it is 216

B.The area of the second enlargement is 1,944 square inches.

True

C.The area of the second enlargement is (3 squared) squared times the original area.

216/24 =9 True

D.The area of the second enlargement is 3 times the area of the first enlargement.

1944/24 = 9 False

E.The ratio of the area of the first enlargement to the area of the original equals the square of the scale factor.

The scale factor is 3 3^2 =9 216/24 =9

True

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1 year ago

a rectangular lawn has an area of a^3 - 125. use the difference of cubes to find out the dimensions of the rectangle.

ANEK [815]

The area of a rectangle is the product of its dimensions

The dimensions of the rectangle are: $\mathbf{Length = a -5}$ and $\mathbf{Width = a^2 + 5a + 25}$

The area is given as:

$\mathbf{Area = a^3 - 125}$

Express 125 as 5^3

$\mathbf{Area = a^3 - 5^3}$

Apply difference of cubes

$\mathbf{Area = (a - 5)(a^2 + 5a + 5^2)}$

$\mathbf{Area = (a - 5)(a^2 + 5a + 25)}$

The area of a rectangle is:

$\mathbf{Area = Length \times Width}$

So, by comparison:

$\mathbf{Length = a -5}$

$\mathbf{Width = a^2 + 5a + 25}$