Given : The waiting time, in hours, between successive speeders spotted by a radar unit is a continuous random variable X with a cumulative distribution function

$F(x)= \begin{cases}0,& x$

Since , the waiting time is in hours , then we can write 12 minutes as $\dfrac{12}{60}$ hour i.e.0.2 hour.

Now, the probability of waiting fewer than 12 minutes between successive speeders is given by :-

$P(X$

Hence, the required probability = 0.5507

4 0

3 years ago

Graph the line y+3=2(x-1) first identify the slope of the line

Mumz [18]

First you need to simplify the equation.

y + 3 = 2(x - 1)
y + 3 = 2x - 2

Then you need to put that into slope-intercept form (y = (slope)x + (y intercept))

y + 3 = 2x - 2
-3 -3
y = 2x - 5

The slope is the coefficient of x, so 2 is the slope of the line.

6 0

3 years ago