You solve for y so then u subtract the 7x from 30 to get 30-7x equals -10 since the -10 has a variable it means u divide by -10 to the subtracting equation to get-3+7/10
Answer:
D
Step-by-step explanation:
if you were to chose c you would find that to negatives make a positive and the first negative has to be there so d would be the best possible answer
Problem:
find line perpendicular to 4x+7y+3=0 passing through (-2,1).
Solution:
We will first find the general form of the perpendicular line.
The perpendicular line has the form
7x-4y+k=0 .........................(1)
by switching the coefficients of x and y, and switching the sign of one of the two coefficients. This way, the slope of (1) multiplied by that of the original equation is -1, a condition that the two lines are perpendicular. The value of k is to be determined from the given point (-2,1).
To find k, we substitute x=-2, y=1 into equation (1) and solve for k.
7(-2)-4(1)+k=0
=>
k=14+4=18
Therefore the required line is
7x-4y+18=0
