Answer:
Just plug in 10^2-7.5^2
To get 43.75
Step-by-step explanation:
I hope you figure this out.
Answer: x^2+29x+39
You would first have to set up an equation, which would be ((2x+9)⋅(x+6))-((x-5)⋅(x-3)) to find the area of both rectangles.
Then you can simplify it, which gives us 2x^2+21x+54-(x^2-8x+15)
Then simplify it even more which gives us 2x^2+21x+54-x^2+8x-15
Then we can get our answer: x^2+29x+39
Hope that helps :)
Answer:
11. False... =2
12. not sure what the answer given is, but it is either 23 or 17.
13. False...=37.15
14. true
15. false...=6
Step-by-step explanation:
P- parentheses
E- exponent
MD- multiply/divide
AS- add/subtract
Options:
a) If corresponding pairs of sides and corresponding pairs of angles of two triangles are congruent, then the triangles can be matched up exactly using rigid motions.
b) If two triangles can be matched up exactly using rigid motions, then the corresponding pairs of sides and corresponding pairs of angles of the triangles are congruent.
c) Two triangles can be matched up exactly using rigid motions if and only if corresponding pairs of sides and corresponding pairs of angles are congruent.
d) If corresponding pairs of sides and corresponding pairs of angles of two triangles are not congruent, then the triangles are not congruent.
Answer:
c) Two triangles can be matched up exactly using rigid motions if and only if corresponding pairs of sides and corresponding pairs of angles are congruent.
Step-by-step explanation:
For both pairs of triangles, what you proved is how to use rigid motions (i.e. rigid transformations) to make congruent shapes.
When rigid transformation is applied to a shape, the image (i.e. result) of the transformation produces an exact shape (i.e. equal corresponding angles and corresponding sides), meaning that the side lengths and the angles of the preimage (before transformation) and the image (after transformation) is unaltered.
<em>Option (c) is true</em>
The greatest number of treats you can buy is 7 because you bought $18 worth of dog food, leaving $7 for treats.