Answer:
Required number is 4.
Step-by-step explanation:
Let the required number be a.
Given,
Sum of ten times the integer and seven times it’s square is 152.
= > Ten times of a + seven times of it's square = 152
= > 10( a ) + 7( a )^2 = 152
= > 10a + 7a^2 - 152 = 0
= > 7a^2 + 10a - 152 = 0
= > 7a^2 + ( 38 - 28 )a - 152 = 0
= > 7a^2 + 38a - 28a - 152 = 0
= > a( 7a + 38 ) - 4( 7a + 38 ) = 0
= > ( a - 4 )( 7a + 38 ) = 0
= > a = 4 or - 38 / 7
Hence the required number is 4.
Answer:
1/3
Step-by-step explanation:
There were 18 students and six liked Much Ado About Nothing. So, you could write this as 6/18 which simplifies to 1/3.
Answer:
- 12 /13
Step-by-step explanation:
Given that:
Cot(θ) = 5 /12 ;
Recall ; cot θ = 1 / tan θ ; tan θ = sin θ / cos θ
Hence ;
tan θ = 1 / cot θ
tan θ = 1 ÷ (5 / 12)
tan θ = 1 * 12 /5 = 12/5
Tan θ = opposite / Adjacent = 12 /5
Sin θ = opposite / hypotenus
Hypotenus = √(opposite² + adjacent²)
Hypotenus = √12² + 5²
Hypotenus = √(144 + 25)
Hypotenus = √169
Hypotenus = 13
Hence,
Sin θ = opposite / hypotenus = 12 / 13
pi < theta < 3pi/2 lies in the 3rd quadrant ; SinΘ will be negative ;
Sin θ = - 12 /13
By straight line angles property,
▶60 + 4x +20 =180
▶80 +4x =180
▶4x = 180 -80
▶4x = 100
x = 25
So, Second angle
▶4 ×25 +20
▶100 + 20
▶120
3x + x =116
4x=116
x = 29
other angle = 3 ×29
=87
ANGLE CAB + ANGLE ACB = 90
2x + x + 30 =90
3x + 30 =90
3x = 90 - 30
3x= 60
x=20
So, angle CAB = 2 ×20 = 40
