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kotegsom [21]
3 years ago
5

Which of the following correctly describes the decimal form of the given number - 13/6

Mathematics
1 answer:
inna [77]3 years ago
8 0

Answer:

2.16 Repeating

Step-by-step explanation:

Convert the fraction to a decimal by dividing the numerator by the denominator.

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19) In the xy-plane, what is the y-intercept of the graph of the equation<br> y=3(x-1)(x+2)?
Dahasolnce [82]

Answer:

- 6

Step-by-step explanation:

Given

y = 3(x - 1)(x + 2) ← expand factors using FOIL

  = 3(x² + x - 2) ← distribute by 3

  = 3x² + 3x - 6

To find the y- intercept let x = 0, thus

y = 3(0)² + 3(0) - 6 = 0 + 0 - 6 = - 6

Thus y- intercept = - 6 ⇒ (0, - 6 )

3 0
3 years ago
Does anyone remember how to do this???? i dont need the steps.
Paladinen [302]

Answer:

im sorry I actually forgot

Step-by-step explanation:

hope we can be friends

can i please get brainliest

4 0
3 years ago
1. The national mean (μ) IQ score from an IQ test is 100 with a standard deviation (s) of 15. The dean of a college wants to kno
Nat2105 [25]

Answer:

We conclude that the mean IQ of her students is different from the national average.

Step-by-step explanation:

We are given that the national mean (μ) IQ score from an IQ test is 100 with a standard deviation (s) of 15.

The dean of a college want to test whether the mean IQ of her students is different from the national average. For this, she administers IQ tests to her 144 students and calculates a mean score of 113

Let, Null Hypothesis, H_0 : \mu = 100 {means that the mean IQ of her students is same as of national average}

Alternate Hypothesis, H_1 : \mu\neq 100  {means that the mean IQ of her students is different from the national average}

(a) The test statistics that will be used here is One sample z-test statistics;

               T.S. = \frac{Xbar-\mu}{\frac{s}{\sqrt{n} } } ~ N(0,1)

where, Xbar = sample mean score = 113

              s = population standard deviation = 15

             n = sample of students = 144

So, test statistics = \frac{113-100}{\frac{15}{\sqrt{144} } }

                             = 10.4

Now, at 0.05 significance level, the z table gives critical value of 1.96. Since our test statistics is more than the critical value of z which means our test statistics will fall in the rejection region and we have sufficient evidence to reject our null hypothesis.

Therefore, we conclude that the mean IQ of her students is different from the national average.

3 0
3 years ago
Solve the equation. If the equation is an identity, choose identity. If it has no solution, choose no solution. 4(t + 2) = 10
Nuetrik [128]

Answer & Step-by-step explanation:

4(t + 2) = 10

4t + 8 = 10

4t = 2

t = 1/2

Hope this helps

3 0
3 years ago
A genetic experiment involving peas yielded one sample of offspring consisting of 409 green peas and 171 yellow peas. Use a 0.05
grigory [225]
The usual expectation for this kind of experiment is that the peas would yield green and yellow peas in a 3:1 ratio, or 75% green to 25% yellow. So your null hypothesis is that the proportion of yellow peas is p=0.25.

You're testing the claim that 26% of the offspring will be yellow, which means the alternative hypothesis is that the proportion of yellow peas is actually 0.26, or more generally that the expected proportion is greater than 0.25, or p>0.25.

The test statistic in this case will be

Z=\dfrac{\hat p-p_0}{\sqrt{\dfrac{p_0(1-p_0)}n}}

where p_0 is the proportion assumed under the null hypothesis, \hat p is the measured proportion, and n is the sample size. You have p_0=0.25, \hat p=\dfrac{171}{171+409}\approx0.29, and n=409+171=580, so the test statistic is

Z=\dfrac{0.29-0.25}{\sqrt{\dfrac{0.25\times0.75}{580}}}\approx2.2247

Because you're testing p>p_0, this is a right-tailed test, so the P-value is

\mathbb P(Z>2.2247)\approx0.0131

The critical value for a right-tail test at a 0.05 significance level is Z_\alpha\approx1.6449, which means the rejection region is any test statistic that is larger than this critical value. Since Z>Z_\alpha in this case, we reject the null hypothesis.

So the conclusion for this test is that the sample proportion is indeed statistically significantly different from the proportion suggested by the null hypothesis.
8 0
3 years ago
Read 2 more answers
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