Answer:
Step-by-step explanation:
1) Let the random time variable, X = 45min; mean, ∪ = 30min; standard deviation, α = 15min
By comparing P(0 ≤ Z ≤ 30)
P(Z ≤ X - ∪/α) = P(Z ≤ 45 - 30/15) = P( Z ≤ 1)
Using Table
P(0 ≤ Z ≤ 1) = 0.3413
P(Z > 1) = (0.5 - 0.3413) = 0.1537
∴ P(Z > 45) = 0.1537
2) By compering (0 ≤ Z ≤ 15) ( that is 4:15pm)
P(Z ≤ 15 - 30/15) = P(Z ≤ -1)
Using Table
P(-1 ≤ Z ≤ 0) = 0.3413
P(Z < 1) = (0.5 - 0.3413) = 0.1587
∴ P(Z < 15) = 0.1587
3) By comparing P(0 ≤ Z ≤ 60) (that is for 5:00pm)
P(Z ≤ 60 - 30/15) = P(Z ≤ 2)
Using Table
P(0 ≤ Z ≤ 1) = 0.4772
P(Z > 1) = (0.5 - 0.4772) = 0.0228
∴ P(Z > 60) = 0.0228
Answer:
A
Step-by-step explanation:
horizontal component=18cos 36.9°≈14.39 m/s≈14.4 m/s
Vertical component=18 sin 36.9°≈10.81 m/s≈10.8 m/s
Answer: 3 inches
Step-by-step explanation:
Answer: No. Kyle will arrive late
Step-by-step explanation:
The only speed limit is 50 miles per hour.
Kyle must cover 130 miles.
His travel time = 130/50 = 2.6
2 hours + (0.6 of 60 minutes )
2 hours + (36 minutes)
i.e kyle needs 2hours 36 minutes to cover 130 miles
And since the baseball starts in 2 hours, kyle will be late. Thus, the answer is No
Answer:
Remember if cosecθ=1/sinθ
sinθ×cosecθ=sinθ×1/sinθ=1
CMIIW
