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3 years ago

How many hundreths need to reach 4 thents

Mathematics

1 answer:

grin007 [14]3 years ago

7 0

Since tenths are 10 hundredths in each, 4 tenths equal to 40 hundredths.

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Evaluate the function f(-2) - h(4) given the following functions: f(x) = 4x 2+ 9 h(x) = 3x - 14

Goryan [66]

Answer:

-86

Step-by-step explanation:

simplify each equation as much as possible

f(x)= 4x(2+9) add

4x(11) multiply

f(x)=44x

substitute given numbers into each equation

44(-2)=-88 3(4)-14= 12-14=-2

combine equations

-88-(-2)= -86 add since you are subtracting a negative number

4 0

3 years ago

A box contains 5 red balls, 6 white balls and 9 black balls. Two balls are drawn at

valina [46]

Answer:

$P(Same)=\frac{61}{190}$

Step-by-step explanation:

Given

$Red = 5$

$White = 6$

$Black = 9$

Required

The probability of selecting 2 same colors when the first is not replaced

The total number of ball is:

$Total = 5 + 6 + 9$

$Total = 20$

This is calculated as:

$P(Same)=P(Red\ and\ Red) + P(White\ and\ White) + P(Black\ and\ Black)$

So, we have:

$P(Same)=\frac{n(Red)}{Total} * \frac{n(Red) - 1}{Total - 1} + \frac{n(White)}{Total} * \frac{n(White) - 1}{Total - 1} + \frac{n(Black)}{Total} * \frac{n(Black) - 1}{Total - 1}$

Note that: 1 is subtracted because it is a probability without replacement

$P(Same)=\frac{5}{20} * \frac{5 - 1}{20- 1} + \frac{6}{20} * \frac{6 - 1}{20- 1} + \frac{9}{20} * \frac{9- 1}{20- 1}$

$P(Same)=\frac{5}{20} * \frac{4}{19} + \frac{6}{20} * \frac{5}{19} + \frac{9}{20} * \frac{8}{19}$

$P(Same)=\frac{20}{380} + \frac{30}{380} + \frac{72}{380}$

$P(Same)=\frac{20+30+72}{380}$

$P(Same)=\frac{122}{380}$

$P(Same)=\frac{61}{190}$

4 0

3 years ago

Think About a Plan Write an indirect proof.

Alekssandra [29.7K]

1) Either $\ell \parallel p$ or $\ell$ ∦ $p$ (only two possibilities)

2) Assume $\ell \parallel p$ (one of two possibilities)

3) $\angle 1 \cong \angle 2$ (if two parallel lines are cut by a transversal, the corresponding angles are congruent)

4) But $\angle 1$ is not congruent to $\angle 2$ (given)

5) So $\ell$ ∦ $p$ (only other possibility)

8 0

2 years ago

Please Help!! Write the function I'm vertex form y = -x^2-2x+6 y=

balu736 [363]

Rewrite in standard form and use the form to find the vertex.

(1, 5)

(x - 1)^2 + 5

7 0

3 years ago

PLEASEEEEE HELP ME yes, hl yes, asa no not enough info yes, sas

podryga [215]

Answer:

a) Yes, HL

Step-by-step explanation:

$We\ know\ that:\\Both\ triangles\ are\ right\ triangles. (90\ degree)\\They\ share\ a\ common\ side.\\They\ have\ their\ hypotenuses\ corresponding.\\Hence,\\Through\ HL(If\ the\ hypotenuse\ and\ any\ leg\ of\ the\ triangles\ are\ corresponding,$ $then,\ the\ two\ triangles\ are\ congruent.)$

$We\ can\ hence,\ conclude\ that\ the\ given\ triangles\ are\ congruent.$

7 0

3 years ago