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2 years ago

Please help me with this it is hard for me but not for my seniors First person with correct answer gets Brainliest answer.

Mathematics

1 answer:

kifflom [539]2 years ago

3 0

Answer:

Step-by-step explanation:

a. 2x + 36

2. 6a + 15b

3. 35x + 15y

4. 3p + 2q

5. 3a + 8

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I really need help please:)

N76 [4]

Answer: the 3rd one or the 1rst one

Step-by-step explanation:

4 0

3 years ago

Conners lawn service charges 5.00 per cut plus 3.50 per gallon of gas used write a algebraic expression To represent the amount

V125BC [204]

Answer:

$5.00 + $3.50g

Step-by-step explanation:

As you mentioned in the question, g = Gallons of gas used

$5.00 + $3.50(g)

Multiply

$5.00 + $3.50g

Hope this helps :)

3 0

3 years ago

If f(x)=-4x^2-6x-1 and g(x)=-x^2-5x+3, fine (f-g)(x)

NeX [460]

Answer:

$\large\boxed{(f-g)(x)=-3x^2-x-4}$

Step-by-step explanation:

$(f-g)(x)=f(x)-g(x)$

$f(x)=-4x^2-6x-1,\ g(x)=-x^2-5x+3\\\\(f-g)(x)=(-4x^2-6x-1)-(-x^2-5x+3)\\\\(f-g)(x)=-4x^2-6x-1-(-x^2)-(-5x)-3\\\\(f-g)(x)=-4x^2-6x-1+x^2+5x-3\qquad\text{combine like terms}\\\\(f-g)(x)=(-4x^2+x^2)+(-6x+5x)+(-1-3)\\\\(f-g)(x)=-3x^2-x-4$

5 0

3 years ago

QUESTION 3 [10 MARKS] A bakery finds that the price they can sell cakes is given by the function p = 580 − 10x where x is the nu

Harman [31]

Answer:

(a)Revenue function, $R(x)=580x-x^2$

Marginal Revenue function, R'(x)=580-2x

(b)Fixed cost =900 .

Marginal Cost Function=300+50x

(c)Profit, $P(x)=-35x^2+280x-900$

(d)x=4

Step-by-step explanation:

Part A

Price Function $= 580 - 10x$

The revenue function

$R(x)=x\cdot (580-10x)\\R(x)=580x-x^2$

The marginal revenue function

$\dfrac{dR}{dx}= \dfrac{d}{dx}(R(x))=\dfrac{d}{dx}(580x-x^2)=580-2x\\R'(x)=580-2x$

Part B

(Fixed Cost)

The total cost function of the company is given by $c=(30+5x)^2$

We expand the expression

$(30+5x)^2=(30+5x)(30+5x)=900+300x+25x^2$

Therefore, the fixed cost is 900 .

Marginal Cost Function

If $c=900+300x+25x^2$

Marginal Cost Function, $\frac{dc}{dx}= (900+300x+25x^2)'=300+50x$

Part C

Profit Function

Profit=Revenue -Total cost

$580x-10x^2-(900+300x+25x^2)\\580x-10x^2-900-300x-25x^2\\$Profit,P(x)=-35x^2+280x-900$

Part D

To maximize profit, we find the derivative of the profit function, equate it to zero and solve for x.

$P(x)=-35x^2+280x-900\\P'(x)=-70x+280\\-70x+280=0\\-70x=-280\\$Divide both sides by -70\\x=4$

The number of cakes that maximizes profit is 4.

6 0

3 years ago

Expand the following: 6(x-4y)

maw [93]

Answer:

to expand, use the distributive property. therefore, we get:

6x - 24y

8 0

3 years ago

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