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givi [52]
3 years ago
12

Part one ) compare 8^0 and 8^-2 which is greater and explain

Mathematics
1 answer:
dusya [7]3 years ago
5 0

8^0 = 1 > 8^-2 = 1/8^2 = 1/64

12^0·12^6 = 1·12^6 = 12^6

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State the domain of the following relation by clicking on the symbols to make the given answer correct.
alekssr [168]

Answer:

  {x: x ∈ ℝ, x ≥ 0}

Step-by-step explanation:

The relation is only defined for non-negative values of x, so that is what the domain consists of: real numbers greater than or equal to zero.

6 0
2 years ago
Factor completely 2x2 − 2x − 40
Montano1993 [528]

Answer:

2(x-5)(x+4)

Step-by-step explanation:

2x^2 − 2x − 40

Factor out a 2

2(x^2 -x -20)

What 2 numbers multiply to -20 and add to -1

-5*4 = -20

-5+4 = -1

2(x-5)(x+4)

4 0
2 years ago
-w + 4(w+3) = -12<br><br> Please help
Ivahew [28]
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4 0
2 years ago
Read 2 more answers
What value of n make this equation true 12(n+6)=96
exis [7]

Answer:

2

Step-by-step explanation:

(6+2)x 12 =96

5 0
2 years ago
Read 2 more answers
Does anyone know the answer
Alex_Xolod [135]

Answer:x = 12,5

using thales's theorem, we have:

\frac{15}{15+36}=\frac{20}{6x-7}\\\\ 6x-7=\frac{20.(15+36)}{15}=68\\\\x = \frac{68+7}{6}=12.5

Step-by-step explanation:

8 0
2 years ago
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