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Otrada [13]
3 years ago
5

Everyday, Kevin has to drive 7 miles each way to work and back. At work, he has to drive his truck on a 296-mile delivery route.

How many miles does he drive during a 5-day workweek?
Mathematics
2 answers:
Vedmedyk [2.9K]3 years ago
6 0

Answer:

1550 miles

Step-by-step explanation:

Every day, he has to drive his car 7 miles to work and 7 miles back, making a total of 14 miles. Adding this to the 296 mile delivery route, that is a total of 310 miles a day. Multiplying this by the 5 days in his workweek, you get a total of 1550 miles. Hope this helps!

NeX [460]3 years ago
5 0

Answer:

idk

Step-by-step explanation:

You might be interested in
Finding the sums
Sav [38]

The sum of the first 7 terms of the geometric series is 15.180

<h3>Sum of geometric series</h3>

The formula for calculating the sum of geometric series is expressed according to the formula. below;

GM = a(1-r^n)/1-r

where

r is the common ratio

n is the number of terms

a is the first term

Given the following parameters from the sequence

a = 1/36

r = -3

n = 7

Substitute

S = (1/36)(1-(-3)^7)/1+3
S = 1/36(1-2187)/4
S = 15.180

Hence the sum of the first 7 terms of the geometric series is 15.180

Learn more on sum of geometric series here: brainly.com/question/24221513

#SPJ1

7 0
1 year ago
The graph of a function is shown:
ziro4ka [17]

Answer:

D) {-2, 1, 2, 5}

Step-by-step explanation:

The "output" of a function will never be an ordered pair, so we can immediately eliminate options A and B.

In this case, the output refers to the y-values of the function.  

Since the ordered pairs are: (-2, 5), (-1, 1), (2, -2), and (5, 2), we see that the output of this function is: 5, 1, -2, 2.

Thus, choice D is correct.

Let me know if this helps!

6 0
3 years ago
I REALLY NEED HELP WILL GIVE EVERYTHING GOOD IF YOU HELP ON 2 MORE
DerKrebs [107]

Answer:

edit: i was wrong ignore me

4 0
3 years ago
f(x) = 2<img src="https://tex.z-dn.net/?f=x%5E%7B2%7D" id="TexFormula1" title="x^{2}" alt="x^{2}" align="absmiddle" class="latex
loris [4]

Answer:

No answer is possible

Step-by-step explanation:

First, we can identify what the parabola looks like.

A parabola of form ax²+bx+c opens upward if a > 0 and downward if a < 0. The a is what the x² is multiplied by, and in this case, it is positive 2. Therefore, this parabola opens upward.

Next, the vertex of a parabola is equal to -b/(2a). Here, b (what x is multiplied by) is 1 and a =2, so -b/(2a) = -1/4 = -0.25.

This means that the parabola opens upward, and is going down until it reaches the vertex of x=-0.25 and up after that point. Graphing the function confirms this.

Given these, we can then solve for when the endpoints of the interval are reached and go from there.

The first endpoint in -2 ≤ f(x) ≤ 16 is f(x) = 2. Therefore, we can solve for f(x)=-2 by saying

2x²+x-4 = -2

add 2 to both sides to put everything on one side into a quadratic formula

2x²+x-2 = 0

To factor this, we first can identify, in ax²+bx+c, that a=2, b=1, and c=-2. We must find two values that add up to b=1 and multiply to c*a = -2  * 2 = -4. As (2,-2), (4,-1), and (-1,4) are the only integer values that multiply to -4, this will not work. We must apply the quadratic formula, so

x= (-b ± √(b²-4ac))/(2a)

x = (-1 ± √(1-(-4*2*2)))/(2*2)

= (-1 ± √(1+16))/4

= (-1 ± √17) / 4

when f(x) = -2

Next, we can solve for when f(x) = 16

2x²+x-4 = 16

subtract 16 from both sides to make this a quadratic equation

2x²+x-20 = 0

To factor, we must find two values that multiply to -40 and add up to 1. Nothing seems to work here in terms of whole numbers, so we can apply the quadratic formula, so

x = (-1 ± √(1-(-20*2*4)))/(2*2)

= (-1 ± √(1+160))/4

= (-1 ± √161)/4

Our two values of f(x) = -2 are (-1 ± √17) / 4 and our two values of f(x) = 16 are (-1 ± √161)/4 . Our vertex is at x=-0.25, so all values less than that are going down and all values greater than that are going up. We can notice that

(-1 - √17)/4 ≈ -1.3 and (-1-√161)/4 ≈ -3.4 are less than that value, while (-1+√17)/4 ≈ 0.8 and (-1+√161)/4 ≈ 2.9 are greater than that value. This means that when −2 ≤ f(x) ≤ 16 , we have two ranges -- from -3.4 to -1.3 and from 0.8 to 2.9 . Between -1.3 and 0.8, the function goes down then up, with all values less than f(x)=-2. Below -3.4 and above 2.9, all values are greater than f(x) = 16. One thing we can notice is that both ranges have a difference of approximately 2.1 between its high and low x values. The question asks for a value of a where a ≤ x ≤ a+3. As the difference between the high and low values are only 2.1, it would be impossible to have a range of greater than that.

7 0
2 years ago
PLS HELP ASAP! IM GIVING U 15 POINTS! PIC INCLUDED! TYSM!
Scilla [17]

Answer: where is the question (and if you think I wrote this to get the points your wrong its because I cant comment ok) so now please show me the question for me and other people to answer.

Step-by-step explanation:

3 0
3 years ago
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