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M1V1=M2V2
M1 * (650 ml) = 0.675 M *450 ml
M1= (0.675 M * 450 ml) / 650 ml
M1= 0.467 M
Answer:
Suppose that at a given point along a capillary, the following forces exist: Capillary hydrostatic pressure (HPc) = 30 mmHg Interstitial fluid hydrostatic pressure (HPif) = 0 mmHg Capillary colloid osmotic pressure (OPc) = 25 mmHg Interstitial fluid colloid osmotic pressure (OPif) = 2 mmHg. The net filtration pressure at this point in the capillary is <u>7mmHg.</u>
Explanation:
Capillary hydrostatic pressure (HPc) = 30 mmHg
Interstitial fluid hydrostatic pressure (HPif) = 0 mmHg
Capillary colloid osmotic pressure (OPc) = 25 mmHg
Interstitial fluid colloid osmotic pressure (OPif) = 2 mmHg
Net filtration pressure= hydrostatic pressure gradient - Oncotic pressure gradient
Hydrostatic pressure gradient = Capillary hydrostatic pressure - Interstitial hydrostatic pressure = 30mmHg - 0 mmHg = 30 mmHg
Oncotic pressure gradient = Capillary colloid osmotic pressure - Interstitial fluid colloid osmotic pressure =25 - 2 = 23 mmHg
Net filtration pressure= hydrostatic pressure gradient - Oncotic pressure gradient = 30 mmHg - 23 mmHg = 7 mmHg.
Hence, The net filtration pressure at this point in the capillary is <u>7mmHg.</u>
