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iVinArrow [24]
3 years ago
8

There are five different colored cards in a hat (red, blue, green, yellow, and black). A card is randomly drawn and not replaced

. Then a second card is drawn. What is the probability that the first card will be red and the second card will be blue?
Mathematics
2 answers:
Mamont248 [21]3 years ago
5 0
The probability that the first card will be red<span>= red cards / total cards = 1/5 = 0.2

</span>the probability that the first card <span>will be blue =</span><span><span> blue cards / total cards = 1/4 = 0.25


1/4 because the cards in the second drawn is 4, not 5 cards</span> </span>



KiRa [710]3 years ago
3 0
|\Omega|=5\cdot4=20\\&#10;|A|=1\\\\&#10;P(A)=\dfrac{1}{20}
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a line whose perpendicular distance from the origin is 4 units and the slope of perpendicular is 2÷3. Find the equation of the l
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Answer:

\huge\boxed{y=\dfrac{2}{3}x-\dfrac{4\sqrt{13}}{3}\ \vee\ y=\dfrac{2}{3}x+\dfrac{4\sqrt{13}}{3}}

Step-by-step explanation:

The equation of a line:

y=mx+b

We have

m=\dfrac{2}{3}

substitute:

y=\dfrac{2}{3}x+b

The formula of a distance between a point and a line:

General form of a line:

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Point:

(x_0,\ y_0)

Distance:

d=\dfrac{|Ax_0+By_0+C|}{\sqrt{A^2+b^2}}

Convert the equation:

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\dfrac{2}{3}x-y+b=0    |<em>multiply both sides by 3</em>

2x-3y+3b=0\to A=2,\ B=-3,\ C=3b

Coordinates of the point:

(0,\ 0)\to x_0=0,\ y_0=0

substitute:

d=4

4=\dfrac{|2\cdot0+(-3)\cdot0+3b|}{\sqrt{2^2+(-3)^2}}\\\\4=\dfrac{|3b|}{\sqrt{4+9}}

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4\sqrt{13}=|3b|\iff3b=-4\sqrt{13}\ \vee\ 3b=4\sqrt{13}   |<em>divide both  sides by 3</em>

b=-\dfrac{4\sqrt{13}}{3}\ \vee\ b=\dfrac{4\sqrt{13}}{3}

Finally:

y=\dfrac{2}{3}x-\dfrac{4\sqrt{13}}{3}\ \vee\ y=\dfrac{4\sqrt{13}}{3}

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