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3 years ago

The area of each circle

Mathematics

1 answer:

Katyanochek1 [597]3 years ago

4 0

Answer:

8. $25\pi$ $in^2$

11. $9\pi$ $m^2$

Step-by-step explanation:

Area = $\pi r^2$

r = d/2

$\pi$ = 3.14

r = 10/2

r = 5 in

Area = $\pi 5^2$

Area = $25\pi$ $in^2$

10.

r = 6/2

r = 3 m

Area = $\pi 3^2$

Area = $9\pi$ $m^2$

Hope it helps! (:

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3 years ago

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Answer:

Figure 1's surface area: 550 $feet^2$

Figure 2's surface area: 530 $feet^2$

Figure 3's surface area: 790 $feet^2$

So, the order of the figures' surface areas is: Figure 2 < Figure 1 < Figure 3.

Step-by-step explanation:

Bearing in mind that the surface area of a 3D object is the total area of its surface (that is the sum of the areas of its faces), we can count the number of distinct shapes in each figure, calculate their areas and add them up. Be careful not to add the faces that are "inside".

<u>Figure 1</u>

Its surface area consists of 13 squares of 5x5 $feet^2$ and 3 rectangles of 15x5 $feet^2$ . So, its surface area is (13x25 + 3x75) $feet^2 = 550feet^2$

<u />

<u>Figure 2</u>

Its surface area consists of 6 squares of 5x5 $feet^2$ , 3 rectangles of 17x5 $feet^2$ , 1 rectangle of 13x5 $feet^2$ and 2 triangles of base 12 feet and height 5 feet. So, its surface area is (17x5x3+6x5x5+13x5+12x5x2:2) $feet^2 = 530feet^2$

<u />

<u>Figure 3</u>

Its surface area consists of 2 rectangles of 12.5x5 $feet^2$ , 1 rectangle of 11x5 $feet^2$ , 2 triangles of base 12 feet and height 5 feet, 1 rectangle of 11x13 $feet^2$ , 2 rectangles of 12.5x11 $feet^2$ and 1 rectangle of 12x11 $feet^2$ .