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MakcuM [25]
3 years ago
7

Bronson is an action and horror movie junkie. He started a movie review vlog and needs to keep up with his movie viewing at a hi

gh pace. It has been a total of 50 weeks since he has stated his vlog and he has watched 1250 movies. He has watched twice as many horror movies as action movies. Write two equations that can model this situation.
Mathematics
1 answer:
andreev551 [17]3 years ago
3 0

two equations which can model this situation is :  y=2x  and  x+y=1250  

<u>Step-by-step explanation:</u>

Here we have , Bronson is an action and horror movie junkie. He started a movie review vlog and needs to keep up with his movie viewing at a high pace. It has been a total of 50 weeks since he has stated his vlog and he has watched 1250 movies. He has watched twice as many horror movies a action movies. We need to Write two equations that can model this situation.​ Let's find out:

Let Bronson watched x action movies and y horror movies , than according to question horror movies he watched is twice that of action movies i.e.

⇒ y=2x       ........(1)

Now ,  he has watched 1250 movies i.e.

⇒ x+y=1250            .......(2)

⇒ x+2x=1250

⇒ 3x=1250

Therefore , two equations which can model this situation is :  y=2x  and  x+y=1250  .

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Answer:

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Step-by-step explanation:

3. What are two ways that a vector can be represented?

Considering a vector \vec{v} in some vector space \mathbb R^n we have

\vec{v} = \langle a,b\rangle

This is the component form. I don't like that way. It is probably used in high school, but

\vec{v} =  \begin{pmatrix} a\\ b\\ \end{pmatrix}

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4.

For this question, I think you meant

vectors

\vec{u_1} = (-8, 12)

\vec{u_2}  = (13, 15)

Once

\cos(\theta)=\dfrac{\vec{u_1} \cdot\vec{u_2}}{||\vec{u_1}||||\vec{u_2}||}

Considering that the dot product is

\vec{u_1}\cdot \vec{u_2} = (-8)\cdot 13 + 12\cdot 15 = -104+180= 76

and the norm of \vec{u_1} is ||\vec{u_1}|| = \sqrt{(-8)^2 + 12^2} = \sqrt{64 + 144}= \sqrt{208}

and the norm of \vec{u_2} is ||\vec{u_2}|| = \sqrt{13^2 + 15^2} = \sqrt{169 + 225}= \sqrt{394}

Thus,

\cos(\theta)=\dfrac{76}{\sqrt{208} \sqrt{394}} = \dfrac{19}{\sqrt{13}\sqrt{394}}=\dfrac{19}{\sqrt{5122}}

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3 0
2 years ago
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Hey there!

\bold{\frac{8(-14)}{(-8)-3(-13)}}

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  • \bold{\frac{-112}{(-8)-3(-13)}}
  • \bold{3\times-13=39}
  • \bold{\frac{-112}{-8-39} }
  • \bold{-8-(-39)=31}
  • \boxed{\boxed{\bold{Answer:\frac{-112}{31}}}}

Good luck on your assignment and enjoy your day!

~\bold{LoveYourselfFirst:)}

7 0
3 years ago
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Ostrovityanka [42]

Answer:

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Step-by-step explanation:

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3 years ago
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Answer:

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