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3 years ago

How many times does 80 go into 480

Mathematics

2 answers:

Margarita [4]3 years ago

3 0

You just divide 480 by 80 to see how many times it can go into.

480/80 = 6

Therefore, 8 goes into 480 6 times.

Hopefully, that helps you.

ale4655 [162]3 years ago

3 0

It can go into it 6 times

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Q.no 21 solve it. <br> Plz. Plz

tekilochka [14]

Answer:

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8 0

2 years ago

Please help me only say something if you really know the answer

Diano4ka-milaya [45]

Answer:

Step-by-step explanation:

Starting with 7,000, after 0 years there will be no increase so you still have 7,000.

The fist year you increase by 5% of 7,000.

.05x7000=350

You have a 350 increase, add that to the original 7000 to find the actual population after 1 year (domain value 1).

After 1 year: 7350

For year 2 there is an increase of 5% again, only this time we find 5% of 7350 since that was the previous years population.

.05x7350=368

Add that to previous population.

368+7350=7718

At this point so far the yearly populations have been (7000, 7350, 7718)

Answer choice B is the only one to have this progression.

3 0

3 years ago

A ball is launched into the sky at 54.4 feet per second from a 268.8 meter tall building. The equation for the ball’s height, h,

worty [1.4K]

Answer:

7.41

Step-by-step explanation:

Vertical component:

S = 268.8

U = 0

V =?

A = 9.8

T=?

S = ut + 0.5at^2. u = 0

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5 0

3 years ago

Read 2 more answers

Evaluate the following integral using trigonometric substitution

serg [7]

Answer:

The result of the integral is:

$\arcsin{(\frac{x}{3})} + C$

Step-by-step explanation:

We are given the following integral:

$\int \frac{dx}{\sqrt{9-x^2}}$

Trigonometric substitution:

We have the term in the following format: $a^2 - x^2$ , in which a = 3.

In this case, the substitution is given by:

$x = a\sin{\theta}$

$dx = a\cos{\theta}d\theta$

In this question:

$a = 3$

$x = 3\sin{\theta}$

$dx = 3\cos{\theta}d\theta$

$\int \frac{3\cos{\theta}d\theta}{\sqrt{9-(3\sin{\theta})^2}} = \int \frac{3\cos{\theta}d\theta}{\sqrt{9 - 9\sin^{2}{\theta}}} = \int \frac{3\cos{\theta}d\theta}{\sqrt{9(1 - \sin^{\theta})}}$

We have the following trigonometric identity:

$\sin^{2}{\theta} + \cos^{2}{\theta} = 1$

$1 - \sin^{2}{\theta} = \cos^{2}{\theta}$

Replacing into the integral:

$\int \frac{3\cos{\theta}d\theta}{\sqrt{9(1 - \sin^{2}{\theta})}} = \int{\frac{3\cos{\theta}d\theta}{\sqrt{9\cos^{2}{\theta}}} = \int \frac{3\cos{\theta}d\theta}{3\cos{\theta}} = \int d\theta = \theta + C$

Coming back to x:

We have that:

$x = 3\sin{\theta}$

$\sin{\theta} = \frac{x}{3}$

Applying the arcsine(inverse sine) function to both sides, we get that:

$\theta = \arcsin{(\frac{x}{3})}$

The result of the integral is:

$\arcsin{(\frac{x}{3})} + C$

8 0

3 years ago

A cat gave birth to 3333 kittens who each had a different mass between 147147147147 and 159 g159\,\text{g}159g159, start text, g

harina [27]

Answer:

The correct option is (B).

Step-by-step explanation:

The median (m) is a measure of central tendency. To obtain the median, we assemble the data in arising order. If the data is odd, the median is the mid-value. If the data is even, the median is the arithmetic-mean of the two mid-values.

The mean of a data set is:

$\bar X=\frac{1}{n}\sum\limits^{n}_{x=0}{X}$

For the three kittens it is provided that the weights are in the range 147 g to 159 g.

So, the mean and median weight for the 3 kittens lies in the middle of this range.

Now a fourth kitten is born, with weight 57 g.

Now the range of the weight of 4 kittens is, 57 g to 159 g.

The mean is going to decrease as one more value is added to the data and the value is the least.

The median will also decrease because now the median will be mean of the 2nd and 3rd values.

But the mean would decrease more than the median because a smaller value is added to the data.

Thus, the correct option is (B).

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3 years ago