When considering similar triangles, we need congruent angles and proportional sides.
Hence
"Angles B and B' are congruent, and angles C and C' are congruent." is sufficient to prove similarity of two triangles.
"Segments AC and A'C' are congruent, and segments BC and B'C' are congruent." does not prove anything because we know nothing about the angles.
"Angle C=C', angle B=B', and segments BC and B'C' are congruent." would prove ABC is congruent to A'B'C' if and only if AB is congruent to A'B' (not just proportional).
"<span>Segment BC=B'C', segment AC=A'C', and angles B and B' are congruent</span>" is not sufficient to prove similarity nor congruence because SSA is not generally sufficient.
To conclude, the first option is sufficient to prove similarity (AAA)
Answer:
Diviértete tratando de conseguirlo porque no sé, así que sí, pero no
Step-by-step explanation:
28 might be a parallelogram
(5,2)(-3,5)
slope = (5 - 2) / (-3 - 5) = -3/8
y = mx + b
slope(m) = -3/8
use either of ur points...(5,2)...x = 5 and y = 2
now we sub and find b, the y int
2 = -3/8(5) + b
2 = - 15/8 + b
2 + 15/8 = b
16/8 + 15/8 = b
31/8 = b
so ur equation is : y = -3/8x + 31/8....or 3x + 8y = 31
Answer:
B. Side <em>a</em> is 7 inches long and side <em>b</em> is 6 inches long.
Step-by-step explanation:
Since the scale drawing is three times bigger than the actual object, divide both numbers by three to find the object size.
Side a:
21/3 = 7 inches
Side b:
18/3 = 6 inches
