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Tema [17]
3 years ago
14

After being rearranged and simplified, which of the following equations could be solved using the quadratic formula?

Mathematics
1 answer:
dmitriy555 [2]3 years ago
3 0
A. 2x^2 - 3x + 10 = 2x + 21
2x^2 - 3x - 2x + 10 - 21 = 0
2x^2 - 5x - 11 = 0                              (quadratic equation)

2x^2 - 6x - 7 = 2x^2
2x^2 - 2x^2 - 6x - 7 = 0
-6x - 7 = 0                                          (not a quadratic equation)

5x^2 + 2x - 4 = 2x^2
5x^2 - 2x^2 + 2x - 4 = 0
3x^2 + 2x - 4                                      (quadratic equation)

5x^3 - 3x + 10 = 2x^2
5x^3 - 2x^2 - 3x + 10 = 0                    (not a quadratic equation)

Therefore, options a and c can be solved using the quadratic formula.
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Answer:  (-\infty, 8)

Step-by-step explanation:

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The steps are:

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