
Step-by-step explanation:
Given





3x - 5y = 18 over
-10x + 5y = 10
Add them because the 5y's have the right symbols for us to add
-7x = 28
Divide
x = -4
Now you can plug in -4 for x in one equation, I would use the first equation!
3(-4) - 5y = 18
-12 - 5y = 18
Add 12
-5y = 30
Divide
y = -6
Your solutions are going to be:
x = -4
y = -6
To check your work plug x and y into one equation:
3(-4) - 5(-6) = 18
-12 + 30 = 18
18 = 18
Since 18 does equal 18 you know that your solution's work!
The option are missing in the question. The options are :
A. P = 2, a = 1
B. 
C. 
D. P = 2, a = 3
Solution :
The given function is 
So for the function to be an exponential growth, a should be a positive number and should be larger than 1. If it less than 1 or a fraction, then it is a decay. If the value of a is negative, then it would be between positive and negative alternately.
When the four option being substituted in the function, we get
A). It is a constant function since 
B). Here, the value of a is a fraction which is less than 1, so it is a decay function. 
C). It is a constant function since the value of a is 1.
D). Here a = 3. So substituting, as the value of x increases by 1, the value of the function, f(x) increases by 3 times.

Therefore, option (D). represents an exponential function.
The answer would be (3,-1) because it is reflected
Answer: A) none of the equations are identities
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Part 1
Plug in theta = 0
sin(theta+pi/2) - cos(theta+pi/6) = 2*cos(theta) - sin(theta)
sin(0+pi/2) - cos(0+pi/6) = 2*cos(0) - sin(0)
1 - sqrt(3)/2 = 2*1 - 0
0.13 = 2
which is a false equation
So we do not have an identity in equation 1.
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Part 2
Plug in theta = 0
sin(theta+pi/6) + cos(theta+pi/3) = (sqrt(2)/3)*sin(theta) + 2*cos(theta)
sin(0+pi/6) + cos(0+pi/3) = (sqrt(2)/3)*sin(0) + 2*cos(0)
1/2 + 1/2 = 0 + 2
1 = 2
which is also false
This is not an identity either.