Answer:
The Second Answer , <em><u>a </u></em><em><u>pattern </u></em><em><u>of </u></em><em><u>two-dimensional </u></em><em><u>shapes </u></em><em><u>that </u></em><em><u>can </u></em><em><u>be </u></em><em><u>folded </u></em><em><u>to </u></em><em><u>form </u></em><em><u>a </u></em><em><u>solid </u></em><em><u>figure </u></em><em><u>.</u></em><em><u> </u></em>
Answer:
- 100
- 80
- 100
- 80
x = 10
y = 6
Step-by-step explanation:
We can use the vertical angle theorem to solve for most of this problem. We know that 1/3 will have the same measure and so will 4/2. We can create an equation to solve for 1 and 3.
10x = 100
x = 10
We aren't given angle 4 so we are going to have to solve that ourselves. We can create an equation knowing that 4 and 3 will create a supplementary angle.
100 + z = 180
z = 80
Now, that we have angle 4, we know that angle 2 will have the same measure because they are vertical angles. Now to find the value of y, we can take the angle measure and solve for it.
10y + 20 = 80
10y = 60
y = 6
Best of Luck!
Answer:

Step-by-step explanation:
Given

Solving (a): Possible union elements
This is the represented by element with the largest number of the sets
i.e.

Solving (b): Possible intersection elements
This is the represented by element with the least number of the sets
i.e.

X^2 + y^2 - 2x + 8y - 47 = 0
x^2 + y^2 - 2x + 8y = 47
(x^2 - 2x) + (y^2 + 8y) = 47
(x^2 - 2(1)x) + (y^2 + 2(4)y) = 47
(x^2 - 2(1)x + 1^2) + (y^2 + 2(4)y + 4^2) = 47 + 1^2 + 4^2
(x - 1)^2 + (y + 4)^2 = 64 = 8^2
r=8