Answer:
The radius of the inflated spherical balloon is 45 millimeters.
Step-by-step explanation:
Volume of the spherical water balloon = 121,500 pi cubic millimeters
Let the radius of the balloon = r
Now, Volume of a Sphere = 
⇒
On solving for the value of r, we get:
![r^{3} = \frac{121,500\times 3}{4} = 91125\\ \implies r = \sqrt[3]{91125}](https://tex.z-dn.net/?f=r%5E%7B3%7D%20%20%3D%20%5Cfrac%7B121%2C500%5Ctimes%203%7D%7B4%7D%20%20%20%3D%2091125%5C%5C%20%5Cimplies%20%20r%20%20%3D%20%5Csqrt%5B3%5D%7B91125%7D)
or, r = 45 millimeter
Hence, the radius of the inflated spherical balloon is 45 millimeters.
Answer:
$50.40 is the answer
Step-by-step explanation:
12% of 45 is 5.40 so if we add $5.40 and $45 we get $50.40
hope this helps ^-^ have a wonderful day
Hello from MrBillDoesMath!
Answer: 13
Discussion:
Evaluate f(g(3)).
g(3) = 3^2 -4 = 5 so
f(g(3)) = f(5) = 3*5-2 = 15 -2 = 13
Thank you,
MrB
Answer:
83 1/3 words per minute
or approximately 83 words per minute
Step-by-step explanation:
4 pages * 250 words/ page = 1000 words
1/5 hour * 60 minutes/ 1 hour = 12 minutes
1000 words / 12 minutes = 83.333333333.... words per minute
83 1/3 words per minute
Answer:
C
Step-by-step explanation:
It is C because I can plot all those points and they are still on the blue line. If you don't believe me, plug them in to y=-3/2x+2, (-4,8 plugged in would look like this 8=-3/2(-4)+2 just plug the x and y coordinates in) and they will be correct.
Hope this helps plz hit the crown:D