The rule of geometric sequence is ⇒⇒⇒ a * r^(n-1)
Where a is the first term and r is the common ratio
for the given sequence √5 , √10 , 2√5 , .......
a = √5
r = √10 / √5 = √2
The ninth term = √5 * (√2)^(9-1) = √5 * (√2)⁸ = 16 √5
the correct answer is the third option 16√5
Answer:
8$
Step-by-step explanation:
4 students contribute 12$ Each.
So, total amount becomes 12 x 4 = 48$
If two more students contribute it makes a total of 6 students.
so we now divide the 48$ by 6
48/6=8$
Hello! Sorry that I'm late. Okay, so each batch calls for 2 2/3 cups of granola and 1 1/3 cups of peanuts. Let's divide the number of cups available total by the amount per batch. To divide fractions, keep the first fraction the same, change division into multiplication, and flip the other faction over. Let's do it. 12/1 * 3/8 = 36/8 or 4 1/2 in mixed number form. 17/2 * 3/4 = 51/8 or 6 3/8 in simplest form. You can only make 4 full batches of trail mix, because you can only use the full serving of both granola AND peanuts for 4 of them.
The cross product of the normal vectors of two planes result in a vector parallel to the line of intersection of the two planes.
Corresponding normal vectors of the planes are
<5,-1,-6> and <1,1,1>
We calculate the cross product as a determinant of (i,j,k) and the normal products
i j k
5 -1 -6
1 1 1
=(-1*1-(-6)*1)i -(5*1-(-6)1)j+(5*1-(-1*1))k
=5i-11j+6k
=<5,-11,6>
Check orthogonality with normal vectors using scalar products
(should equal zero if orthogonal)
<5,-11,6>.<5,-1,-6>=25+11-36=0
<5,-11,6>.<1,1,1>=5-11+6=0
Therefore <5,-11,6> is a vector parallel to the line of intersection of the two given planes.
