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nikitadnepr [17]
3 years ago
11

A group of students go out on a boat to go scuba diving. The instructor takes the group 57.52 feet below the surface to start. T

hen they go up 24.88 feet and stop to see some fish. Estimate the total change in distance from where they started at the surface. Find the total change in distance from where they started at the surface..
Mathematics
1 answer:
erastova [34]3 years ago
8 0

Answer:

it is  82.13

Step-by-step explanation:

you can add the 57.52+24.88

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Answer:

99% CI:

-4.637\leq\mu_v-\mu_o\leq 3.737

Step-by-step explanation:

We have to calculate a 99%CI for the difference of means for the vegan and the omnivore.

First, we have to estimate the standard deviation

s_{Md}=\sqrt{\frac{2MSE}{n_h}}

The MSE can be calculated as

MSE=\frac{(SSE_1+SSE_2)}{df} =\frac{(n_1s_1)^2+(n_2*s_2)^2}{n_1+n_2-2}\\\\MSE=\frac{(85*1.05)^2+(96*1.20)^2}{85+96-2}=\frac{7965.56+13272.04}{179} =118.65

The weighted sample size nh can be calculated as

n_h=\frac{2}{1/n_1+1/n_2}=\frac{2}{1/85+1/96}=\frac{2}{0.0222} =90.16

The standard deviation then becomes

s_{Md}=\sqrt{\frac{2MSE}{n_h}}=\sqrt{\frac{2*118.65}{90.16}}=\sqrt{2.632} =1.623

The z-value for a 99% confidence interval is z=2.58.

The difference between means is

\Delta M=M_v-M_o=5.10-5.55=-0.45

Then the confidence interval can be constructed as

\Delta M-z*s_{Md}\leq\mu_v-\mu_o\leq \Delta M+z*s_{Md}\\\\ -0.45-2.58*1.623\leq\mu_v-\mu_o\leq -0.450+2.58*1.623\\\\-0.450-4.187\leq\mu_v-\mu_o\leq-0.450+4.187\\\\-4.637\leq\mu_v-\mu_o\leq 3.737

8 0
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The graph show the grades that students received on a test. What percent of the students received a grade of A ?
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Answer:

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Step-by-step explanation:

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Use the figure and flowchart Proof to answer the question which property of equality accurately completes reason C
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Answer:

Step-by-step explanation:

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7 0
3 years ago
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Combine and simplify the following radical expression <br><br> ASAP ASAP ASAP ASAP
Montano1993 [528]

Answer:

\sqrt[3]{3}

Step-by-step explanation:

Our expression is: \frac{1}{3} \sqrt[3]{81}.

Let's focus on the cube root of 81 first. What's the prime factorisation of 81? It's simply: 3 * 3 * 3 * 3, or 3^3*3. Put this in for 81:

\sqrt[3]{81} =\sqrt[3]{3^3*3}=\sqrt[3]{3^3} *\sqrt[3]{3}

We know that the cube root of 3 cubed will cancel out to become 3, but the cube root of 3 cannot be further simplified, so we keep that. Our outcome is then:

\sqrt[3]{3^3} *\sqrt[3]{3}=3\sqrt[3]{3}

Now, let's multiply this by 1/3, as shown in the original problem:

\frac{1}{3}* 3\sqrt[3]{3}=\sqrt[3]{3}

Thus, the answer is \sqrt[3]{3}.

<em>~ an aesthetics lover</em>

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3 years ago
Please please help I really need it today please show work
Cerrena [4.2K]

Answer:

<u><em>x=9</em></u>.

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<em><u>area=168</u></em>

Step-by-step explanation:

First find the side that has a exact number which would be the bottom 28cm then look at the opposite side (2x+10) in order to find x subtract 10 from 28 which gives you 18, now 2x means x multiplied by 2 so what multiplied by 2 = 18? 9 meaning <u><em>x=9</em></u>. Now you are going to want to plug 9 in to your short side (x-3) once you plug it in it should look like this 9-3 and 9-3=6 meaning the short side is 6cm. In order for you to find the perimeter you have to add the sides together so 28+28+6+6 wich <u><em>=68</em></u> and in order for you to find the area you have to  multiply the length and the width so 28x6 which is <em><u>168</u></em>.

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