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tekilochka [14]
3 years ago
6

The first three terms of a sequence are given. Round to the nearest thousandth (if necessary).

Mathematics
1 answer:
zalisa [80]3 years ago
8 0

Answer: 272

Step-by-step explanation:

Let a1=11

a2=20

a3=29

Formula for sequence=

an=a1+(n-1)d

an = nth term

a1= first term

n= nth position

d= common difference

We are looking for the 30th term,so our n=30

d= a2-a1

d= 20-11

d= 9

Using the formula

an= a1+(n-1)d

a30= 11+(30-1)9

a30= 11+(29)9

a30= 11+(29×9)

a30= 11+261

a30= 272

Therefore, the 30th term is 272

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Explain why any of the four operations placed between two terms 5 and -3 sqrt (8) will result in an irrational number
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Sum/difference:

Let

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This means that

3\sqrt{8} = 5-x \iff \sqrt{8} = \dfrac{5-x}{3}

Now, assume that x is rational. The sum/difference of two rational numbers is still rational (so 5-x is rational), and the division by 3 doesn't change this. So, you have that the square root of 8 equals a rational number, which is false. The mistake must have been supposing that x was rational, which proves that the sum/difference of the two given terms was irrational

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The logic is actually the same: if we multiply the two terms we get

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3 years ago
Suppose that salaries for recent graduates of one university have a mean of $25,700 with a standard deviation of $1350. Using Ch
sergeinik [125]

Answer:

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To find the range of values :

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