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Anna11 [10]
3 years ago
5

You were planning on reading the last book of the hunger games. The book is 350 pages long and you have read 3/5 of the book so

far how many pages do you have left to Read??????
Mathematics
1 answer:
Gemiola [76]3 years ago
4 0

I believe it is 210. I did 350 x 3/5 on a calculator, and that's what I got.

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T. Dr. Sox drives through two stoplights on
kiruha [24]

Question??

Dr. Sox drives through two stoplights on her way to work. The first light is green for 20 seconds out of each minute. The second light is green for 35 seconds out of each minute. What is the probability that Dr. Sox will hit two green lights?

Explanation;

Since this is an AND situation, we MULTIPLY the probabilities.

Answer/Explanation:

First light green:

P

1

=

20

60

=

1

3

Second light green:

P

2

=

35

60

=

7

12

Both lights green:

P

=

P

1

×

P

2

=

1

3

×

7

12

=

7

36

Of course, this is assuming that there is no "green wave" policy, or the two probabilities would not be independent

7 0
3 years ago
Which of the following is the result of expanding 4 £ n=1 (2n-3)
geniusboy [140]

Answer: 8

Step-by-step explanation: the given expression is 2n-3

so when n=1, we will get, 2(1)-3=2-3=-1

when n=2, we will get, 2(2)-3= 4-3=-1

when n=3, we will get 2(3)-3= 6-3=3

when n=4, we will get 2(4)-3 = 8-3=5

so the required result of expansion is -1+1+3+5=8

answer is 8.

hope that helped!

3 0
4 years ago
What is the value of log Subscript 6 Baseline StartFraction 1 Over 36 EndFraction?
loris [4]

Answer:

-2

Step-by-step explanation:

Let  x be the unknown value  

Log₆  ( 1/36) = x

( 1/36) = 36⁻¹ = (6²)⁻¹ = 6⁻²

Log₆  ( 1/36) = Log₆ 6⁻²  = -2 Log₆ 6

Log₆ 6 = 1

-2 Log₆ 6 = -2(1) = -2

4 0
4 years ago
Read 2 more answers
Amy has 6 blue, 2 red, and 4 green books to arrange on a shelf. in how many ways can the books be arranged if books of the same
Semmy [17]
There are 6! possible permutations of the blue books, 2 possible permutations of the red books, 4! possible permutations of the green books and 3! possible permutations of the three color groups. therefore the total number of ways of arranging the books is given by:
6!\times2\times4!\times3!=207360\ ways
5 0
3 years ago
Read 2 more answers
How many different 10 person committees can be selected from a pool of 23 people?
Salsk061 [2.6K]

We're going to be using combination since this question is asking how many different combinations of 10 people can be selected from a set of 23.

We would only use permutation if the order of the people in the committee mattered, which it seems it doesn't.

Formula for combination:

C(n,r)=\dfrac{n!}{(n-r)!r!}

Where n represents the number of objects/people in the set and r represents the number of objects/people being chosen from the set

There are 23 people in the set and 10 people being chosen from the set

C(23,10)=\dfrac{23!}{(23-10)!10!}

=\dfrac{23!}{13!\times10!}

Usually I would prefer solving such fractions by hand instead of a calculator, but factorials can result in large numbers and there is too much multiplication. Using a calculator, we get

=1,144,066

Thus, there are 1,144,066 different 10 person committees that can be selected from a pool of 23 people. Let me know if you need any clarifications, thanks!

~ Padoru

4 0
3 years ago
Read 2 more answers
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