Find the measure of the given arc in Circle C.

Pairs of angles nonadjacent formed when a transversal intersects two lines so that they lie on the same side of the transversal

Solnce55 [7]

Answer:

Corresponding Angles

Step-by-step explanation:

Corresponding Angles

3 0

3 years ago

Help me all the questions, explain you answers plssssss

BartSMP [9]

Is there a grid that came with the problem?

8 0

3 years ago

Item 10 At 1:00 P.M., you have 24 megabytes of a movie. At 1:15 P.M., you have 96 megabytes. What is the download rate in megaby

alex41 [277]

Answer:

4.8 megabytes / minute.

Step-by-step explanation:

At the beginning of recording the download you have 24 megabytes.

15 minutes later, you have 96 megabytes.

In 15 minutes you have downloaded 96 - 24 = 72 megabytes

So the question turns out to be a proportion of

x megabytes / 1 minute = 72 megabytes / 15 minutes.

x = 72/15

x = 4.8 megabytes / minute

3 0

3 years ago

A professor wishes to discover if seniors skip more classes than freshmen. Suppose he knows that freshmen skip 2% of their class

KIM [24]

Answer:

We conclude that seniors skip more than 2% of their classes at 0.01 level of significance.

Step-by-step explanation:

We are given that a professor wishes to discover if seniors skip more classes than freshmen. Suppose he knows that freshmen skip 2% of their classes.

He randomly samples a group of seniors and out of 2521 classes, the group skipped 77.

Let p = percentage of seniors who skip their classes.

So, Null Hypothesis, $H_0$ : p $\leq$ 2% {means that seniors skip less than or equal to 2% of their classes}

Alternate Hypothesis, $H_A$ : p > 2% {means that seniors skip more than 2% of their classes}

The test statistics that will be used here is One-sample z proportion statistics;

T.S. = $\frac{\hat p-p}{{\sqrt{\frac{\hat p(1-\hat p)}{n} } } } }$ ~ N(0,1)

where, $\hat p$ = sample proportion of seniors who skipped their classes = $\frac{77}{2521}$

n = sample of classes = 2521

So, test statistics = $\frac{\frac{77}{2521} -0.02}{{\sqrt{\frac{\frac{77}{2521}(1-\frac{77}{2521})}{2521} } } } }$

= 3.08

The value of the test statistics is 3.08.

Now at 0.01 significance level, the z table gives critical value of 2.3263 for right-tailed test. Since our test statistics is more than the critical value of z as 2.3263 < 3.08, so we have sufficient evidence to reject our null hypothesis as it will fall in the rejection region due to which we reject our null hypothesis.

Therefore, we conclude that seniors skip more than 2% of their classes.

6 0

3 years ago

If 3 Onions Weigh 0.75lb how much do 10 onions weigh

fomenos

First find out how much one onion weighs so divide 0.75 by 3. This gets you 0.25. Now all you need to do is multiply the weight of one onion by 10, 0.25 x 10 = 2.5

3 0

3 years ago

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